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Q: What are two consecutive even integers that equal 126?

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:/ We can write it this way: x - 1 + x + x + 1 = 126. 1s cancel out, so we get 3x = 126. 126/3 = 42. Answer: 41, 42, 43.

60/126 = 30/63 = 10/21

1, 9, 36, 84, 126, 126, 84, 36, 9, 1

1 9 36 84 126 126 84 36 9 1

21

Related questions

The two even consecutive integers are: 62+64 = 126

There is no solution. Since 126 is even and two consecutive integers have to be one odd and one even number, an odd and an even number cannot summate to an even number.

63+83=126.... hope it helps!

The numbers are 62 and 64.

Divide 126 by 2 and choose the even numbers on both sides.

41,42,43

41+42+43=126.

The integers are are 41, 42 and 43.

Let the intgers be n- 1 n , & n+1 . This is consecutive. Hence Adding (n-1) + n + ( n +1) = 126 Add the LHS 3n = 126 Divide both sides by '3' n = 42 Hence n- 1 = 41 & n +1 = 43 So the consecutive integers are 41,42, & 43.

The numbers are 125 and 126.

41, 42 and 43

41, 42 and 43

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