63+83=126.... hope it helps!
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2 times 30+31+32+33 41+42+43
125, 126 and 127.
The numbers are 41, 42 and 43.
127 is between the integers 126 and 128.
Let the consecutive multiples of 7 be 7x and 7(x+1).7x + 7(x+1) = 1267x + 7x + 7 = 12614x + 7 + 12614x = 126 - 714x = 119x = 119/14x = 8.5For 7x to be a multiple of 7, x must be a whole number, so there are no such consecutive multiples.