1. Number of diagonals = 0.5*(n2-3n) where n represents the number of sides
2. If a polygon had 8 sides write out the numbers in descending order leaving out the first 2 numbers and the last number and adding them up gives the amount of diagonals:-
6+5+4+3+2 = 20 diagonals
If it had 9 sides then do the same:-
7+6+5+4+3+2 = 27 diagonals
The diagonals (drawn from a point) help in dividing the regular polygon into smaller triangles. The sum of the areas of these smaller triangles help in determining the total area of the polygon.
It has 20 diagonals
14 diagonals
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
It works out that a polygon with 1175 diagonals has 50 sides
Total diagonals formula: 0.5*(n^2 -3n) whereas n is the number of sides of the polygon
Finding the perimeter of a polygon is finding how far it is in total along all the edges of the polygon; whereas finding the area of a polygon is finding how much space the polygon covers. The perimeter of a polygon forms the boundary around the area of the polygon.
An eight-sided polygon has 8 vertices. Consider1st vertex = 7 diagonals to other vertices2nd vertex = 6 diagonals to other vertices (since one has now been used)3rd vertex = 54th vertex = 45th vertex = 36th vertex = 27th vertex = 18th vertex = 0, so7+6+5+4+3+2+1 = 28Improved Answer:-Formula for finding diagonals of a polygon 0.5*(n2-3n) when n is the number of sides0.5*(82-24) = 20 diagonals
If it is a regular polygon with each interior angle of 120 degrees then it is an hexagon which will have 0.5((6^2)-3*6) equals 9 diagonals
The formula is: 0.5*(n2-3n) whereas n is the number of sides So: 0.5*(352-105) = 560 diagonals
Suppose the polygon has V vertices.Then sum of interior angles is (V - 2)*180 degrees = 1980 degrees => V - 2 = 1980/180 = 11 => V = 13 A polygon with V vertices has V*(V-3)/2 = 13*10/2 = 65 diagonals.
Using the formula 0.5(n^2 -3n) whereas n is number of sides, altogether there are 104 diagonals in a 16 sided polygon