Total diagonals formula: 0.5*(n^2 -3n) whereas n is the number of sides of the polygon
There are two diagonals in a trapezoid.
14 diagonals
It has 20 diagonals
It has 0 volume diagonals and 6 face diagonals hence the total number of diagonals are 6
None
14
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
A 7 sided septagon or heptagon has 14 diagonals
It is: 0.5*(10 squared - (3*10)) = 35 diagonals
From each vertex, N-4 diagonals can be drawn, where N is the number of vertices. The total number of diagonals in a prism will be N(N-4)/2, where N is the number of vertices. For N=12 (a hexagonal prism) The total number of diagonals is 12*8/2=48 Answer:48
A nonagonal prism has two nonagonal bases and rectangular lateral faces. To find the total number of diagonals in a nonagonal prism, we first calculate the diagonals in one nonagon, which is given by the formula ( \frac{n(n-3)}{2} ). For a nonagon ((n = 9)), this results in 27 diagonals. Since the prism has two bases, the total number of diagonals in the prism is ( 27 + 27 + 18 = 72 ), where the 18 comes from the diagonals connecting vertices from one base to the other.
The formula is: 0.5*(n2-3n) whereas n is the number of sides So: 0.5*(352-105) = 560 diagonals