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How do you get the total number of diagonals of a polygon?
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
What is the Practical application for finding the number of diagonals in a regular polygon?
The diagonals (drawn from a point) help in dividing the regular polygon into smaller triangles. The sum of the areas of these smaller triangles help in determining the total area of the polygon.
What is the total number of diagonals in a regular polygon with an interior angle of 120 degrees?
If it is a regular polygon with each interior angle of 120 degrees then it is an hexagon which will have 0.5((6^2)-3*6) equals 9 diagonals
Total of 1175 diagonal can be drawn in a polygon?
It works out that a polygon with 1175 diagonals has 50 sides
What is the total number of diagonal lines for a hexagon?
The total number of diagonals for a convex (or concave) polygon, a hexagon being of the former type, is given by the equation (n2 - 3n)/2, where n is the number of sides of the polygon. A hexagon has 6 sides, so plugging the number 6 into the above equation for n, one finds that a hexagon has: [62 - 3(6)]/2 = (36 - 18)/2 = 18/2 = 9 diagonals.
What is the total number of diagonals in a polygon with eight sides?
It has 20 diagonals
How do you get the total number of diagonals of a polygon?
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
What is the total number of diagonals?
Total diagonals formula: 0.5*(n^2 -3n) whereas n is the number of sides of the polygon
What is the Practical application for finding the number of diagonals in a regular polygon?
The diagonals (drawn from a point) help in dividing the regular polygon into smaller triangles. The sum of the areas of these smaller triangles help in determining the total area of the polygon.
What is the total number of diagonals in a 35 sided polygon?
The formula is: 0.5*(n2-3n) whereas n is the number of sides So: 0.5*(352-105) = 560 diagonals
What is the total number of diagonals in a regular polygon with an interior angle of 120 degrees?
If it is a regular polygon with each interior angle of 120 degrees then it is an hexagon which will have 0.5((6^2)-3*6) equals 9 diagonals
How many diagonals from one vertex in 16gon?
Using the formula 0.5(n^2 -3n) whereas n is number of sides, altogether there are 104 diagonals in a 16 sided polygon
Total of 1175 diagonal can be drawn in a polygon?
It works out that a polygon with 1175 diagonals has 50 sides
What is the total number of diagonals in a trapezoid?
There are two diagonals in a trapezoid.
What is the total number of diagonal lines for a hexagon?
The total number of diagonals for a convex (or concave) polygon, a hexagon being of the former type, is given by the equation (n2 - 3n)/2, where n is the number of sides of the polygon. A hexagon has 6 sides, so plugging the number 6 into the above equation for n, one finds that a hexagon has: [62 - 3(6)]/2 = (36 - 18)/2 = 18/2 = 9 diagonals.
What are two numerical ways in finding the total sum of diagonals in any polygon?
1. Number of diagonals = 0.5*(n2-3n) where n represents the number of sides2. If a polygon had 8 sides write out the numbers in descending order leaving out the first 2 numbers and the last number and adding them up gives the amount of diagonals:-6+5+4+3+2 = 20 diagonalsIf it had 9 sides then do the same:-7+6+5+4+3+2 = 27 diagonals
How many diagonals can be drawn from one vertex of a polygon of 50 sides?
47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.
