a dot
the y-axis is vertical, and the x- axis is horizontal
It will look like a straight vertical line that cuts the x-axis at the point (100, 0).
it will be pointing to the right side of the plane
Yes, a parabola always has a vertex. However, it may not always have roots. The roots of a parabola are the x-values where the parabola intersects the x-axis. It is possible for a parabola to have two, one, or no roots depending on the discriminant of the quadratic equation.
the x-axis goes horizontally (like this _______ ) and the y-axis goes vertically (like this | )
When the vertex lies on the x-axis. For example x = y2, the vertex is at the origin, and the parabola is lying on its side.
the x-axis... obviously! the x-axis... obviously!
the y-axis is vertical, and the x- axis is horizontal
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
The axis of symmetry is x = -2.
It is (-1, 3).
2
It would look like a straight vertical line, i.e. parallel to the y-axis, passing through the point on the x-axis where x=3.
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)
It will look like a straight vertical line that cuts the x-axis at the point (100, 0).