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The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
y=x2-10x+30=(x-5)2-25+30=(x-5)2+5
To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).
By inspection you should be able to see that this is a parabola with a vertex of this. (0, 0) There is no form for this function as there is no linear term.
y=2(x-3)+1
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
The vertex form for a quadratic equation is y=a(x-h)^2+k.
y=x2-10x+30=(x-5)2-25+30=(x-5)2+5
2
The vertex form is y = (x - 4)2 + 13
The question does not contain an equation: only an expression. An expression cannot have a vertex form.
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
The difference between standard form and vertex form is the standard form gives the coefficients(a,b,c) of the different powers of x. The vertex form gives the vertex 9hk) of the parabola as part of the equation.
Assume the expression is: y = x² - 10x + 30 Complete the squares to get: y = x² - 10x + 25 + 30 - 25 = (x - 5)² + 5 So the expression is in vertex form y = (x - h)² + k
-2
please help
To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).