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How do you write y equals x minus 4 x plus 2 in vertex form and find the vertex?

The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.


What is the equation for vertex form?

The vertex form for a quadratic equation is y=a(x-h)^2+k.


Which equation represents y equals x2-10x plus 30 in vertex form?

y=x2-10x+30=(x-5)2-25+30=(x-5)2+5


The vertex of the parabola below is at the point -3 -5 Which of the equations below could be the equation of this parabola?

2


What is the equivalent of the following equation y equals x2 - 8x plus 29?

The vertex form is y = (x - 4)2 + 13


What is the vertex form of y -4x2-6x?

The question does not contain an equation: only an expression. An expression cannot have a vertex form.


What different information do you get from vertex form and quadratic equation in standard form?

The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.


What is the difference between standard form and vertex form?

The difference between standard form and vertex form is the standard form gives the coefficients(a,b,c) of the different powers of x. The vertex form gives the vertex 9hk) of the parabola as part of the equation.


Which equation represents yx2-10x 30 in vertex form?

Assume the expression is: y = x² - 10x + 30 Complete the squares to get: y = x² - 10x + 25 + 30 - 25 = (x - 5)² + 5 So the expression is in vertex form y = (x - h)² + k


The vertex of the parabola below is at the point (-4-2) which equation below could be one for parabola?

-2


What is an equation of the parabola in vertex form that passes through (13 8) and has vertex (3 2).?

please help


How do you find the vertex of an equation in standard form?

To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).