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What is an equation of the parabola in vertex form that passes through (13 8)(13 8) and has vertex (3 2)(3 2).?
Vertex form is denoted by: y=a(x-h)2+k Where (h,k) is the vertex. So, we have: y=a(x-2)2+3 (This super\subscript thing is annoying). Plug in the values for x and y for the point in the equation and you have your answer.
Find equation what parabola its vertex is 0 0 and it passes through point 2 12 express the equation in standard form?
Y=3x^2 and this is in standard form. The vertex form of a prabola is y= a(x-h)2+k The vertex is at (0,0) so we have y=a(x)^2 it goes throug (2,12) so 12=a(2^2)=4a and a=3. Now the parabola is y=3x^2. Check this: It has vertex at (0,0) and the point (2,12) is on the parabola since 12=3x2^2
Which equation represents yx2-10x 30 in vertex form?
Assume the expression is: y = x² - 10x + 30 Complete the squares to get: y = x² - 10x + 25 + 30 - 25 = (x - 5)² + 5 So the expression is in vertex form y = (x - h)² + k
What is the equivalent of the following equation y equals x2 - 8x plus 29?
The vertex form is y = (x - 4)2 + 13
How do you convert y x2 4x - 7 into vertex form?
http://www.algebra.com/algebra/homework/Polynomials-and-rational-expressions/completing-the-square.solvergo to this address for step by step instructions on this and the answer. just plug in you a, b, and c value and your off!
