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What is an equation of the parabola in vertex form that passes through (13 8)(13 8) and has vertex (3 2)(3 2).?
Vertex form is denoted by: y=a(x-h)2+k Where (h,k) is the vertex. So, we have: y=a(x-2)2+3 (This super\subscript thing is annoying). Plug in the values for x and y for the point in the equation and you have your answer.
Find equation what parabola its vertex is 0 0 and it passes through point 2 12 express the equation in standard form?
Y=3x^2 and this is in standard form. The vertex form of a prabola is y= a(x-h)2+k The vertex is at (0,0) so we have y=a(x)^2 it goes throug (2,12) so 12=a(2^2)=4a and a=3. Now the parabola is y=3x^2. Check this: It has vertex at (0,0) and the point (2,12) is on the parabola since 12=3x2^2
Which equation represents yx2-10x 30 in vertex form?
Assume the expression is: y = x² - 10x + 30 Complete the squares to get: y = x² - 10x + 25 + 30 - 25 = (x - 5)² + 5 So the expression is in vertex form y = (x - h)² + k
How do you convert y x2 4x - 7 into vertex form?
http://www.algebra.com/algebra/homework/Polynomials-and-rational-expressions/completing-the-square.solvergo to this address for step by step instructions on this and the answer. just plug in you a, b, and c value and your off!
What is the equivalent of the following equation y equals x2 - 8x plus 29?
The vertex form is y = (x - 4)2 + 13
What is the equation for vertex form?
The vertex form for a quadratic equation is y=a(x-h)^2+k.
How do you write y equals x minus 4 x plus 2 in vertex form and find the vertex?
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
Where is the vertex of a parabola?
when the function is in vertex form: y = a(x - h)2 + k, the point (h, k) is the vertex.
What is vertex form?
y=a(x-h)2+k
What is the vertex form of y equals 6x2?
By inspection you should be able to see that this is a parabola with a vertex of this. (0, 0) There is no form for this function as there is no linear term.
What is an equation of the parabola in vertex form that passes through (13 8)(13 8) and has vertex (3 2)(3 2).?
Vertex form is denoted by: y=a(x-h)2+k Where (h,k) is the vertex. So, we have: y=a(x-2)2+3 (This super\subscript thing is annoying). Plug in the values for x and y for the point in the equation and you have your answer.
How do you find the vertex of a parabola when the equation is in standard form?
To find the vertex of a parabola in standard form, which is given by the equation ( y = ax^2 + bx + c ), you can use the formula for the x-coordinate of the vertex: ( x = -\frac{b}{2a} ). Once you have the x-coordinate, substitute it back into the original equation to find the corresponding y-coordinate. The vertex will then be at the point ( (x, y) ).
What is the vertex form of y equals x2 plus 4x - 7?
The vertex of the positive parabola turns at point (-2, -11)
How do you convert standard form to vertex form?
y= -5/49(x-9)^2+5
Find equation what parabola its vertex is 0 0 and it passes through point 2 12 express the equation in standard form?
Y=3x^2 and this is in standard form. The vertex form of a prabola is y= a(x-h)2+k The vertex is at (0,0) so we have y=a(x)^2 it goes throug (2,12) so 12=a(2^2)=4a and a=3. Now the parabola is y=3x^2. Check this: It has vertex at (0,0) and the point (2,12) is on the parabola since 12=3x2^2
What is the formula for quadratic equation in vertex form?
y=2(x-3)+1
What is the vertex form of a parabola that opens left?
It is (y - b)^2 = ax + c
