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Q: What is (y2 and minus x5) and minus ( and minusx5 and minus x2)?
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What is the formula to calculate the slope?

It's m = y2 - y1/ x2- x1 It's m equals y2 minus y1 over x2 minus x1


How do you find the slope?

y2(minus)y1 ---------------(over) x2(minus)x1


Factorise x2 minus y2 plus 9x minus 9y?

x2 - y2 + 9x - 9y =(x2 + 9x) - (y2 + 9y) =x(x + 9) - y(y + 9)================================Another way to go after it:x2 - y2 + 9x - 9y =(x2 - y2) + 9x - 9y =(x + y) (x - y) + 9 (x - y) =(x + y + 9) (x - y)


How do you factor x2 minus y2?

(x - y)(x + y)


What is x minus y in parenthesis squared?

(x - y)2 = x2 - 2xy + y2


What is the expansion for x2 plus y2?

There is no expansion for x2 + y2


Convert x2 plus y2 equals 2x?

What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2


The circle is centered at the origin and the length of its radius is 8 What is the circle's equation?

The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.


How do you factor x to the sixth minus y to the sixth?

x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)


How do you draw a square using line command?

Line (x1, y1, x2, y1); Line (x2, y1, x2, y2); Line (x2, y2, x1, y2); Line (x1, y2, x1, y1);


How can you graph x2 - y2 equals 9?

Therefore x2=9+y2. And x is the square-root of that (with two values plus and minus). Choose a value of y, and work out x2 and therefore the values of x. Plot the two (+ and -) on a graph and continue for more values of y.


When using the slope formula does it have to be (y2-y1)(x2-x1) or can it be (y1-y2)(x1-x2)?

If you mean: (y2-y1)/(x2-x1) and (y1-y2)/(x1-x2) then either works out the same.