In its most simplified form:
= 12abc + 8bc - 20ab
= 4b(3ac + 2c - 5a)
= 4b[(c + 5/3)(3a + 2) - 10/3]
The GCF is 4ab.
The expression (-4ad - 8bc) cannot be simplified further without additional information about the variables (a), (b), (c), and (d). It represents a linear combination of the terms (-4ad) and (-8bc). If you need a specific evaluation, values for the variables must be provided.
30, because their was no year zero
Are you sure that the given expressions are right? Because we are dealing with complex numbers (a little bit work for this kind of exercise).ab = 4x + 8bc = 8x + 4ac = 18x - 11b = a/(4x + 8)c = b/(8x + 4) = [a/(4x + 8)[/(8x + 4) = a/[(4x + 8)(8x + 4)]c = a/(18x - 11)a/[(4x + 8)(8x + 4)] = a/(18x - 11) this happens only when:(4x + 8)(8x + 4) = (18x - 11)32x^2 + 16x + 64x + 32 = 18x - 1132x^2 + 62x + 43 = 0x = [-62 ± √(62^2 - (4)(32)(43)]/[(2)(32)]x = [-62 ± √(-1660)]/64x = [-62 ± i√(1660)]/64x = -62/64 ± i√(1660/4096) (64^2 = 4096)x = -31/32 ± i√[415/1024]Substitute -31/32 ± i√[415/1024] for x, and find the value of ab, bc, and ac.ab = 4x + 8bc = 8x + 4ac = 18x - 11
76 plus 54 plus 92 plus 88 plus 76 plus 88 plus 75 plus 93 plus 92 plus 68 plus 88 plus 76 plus 76 plus 88 plus 80 plus 70 plus 88plus 72 equal 1,440
15a + 20ab = zero5a(3 + 4b) = zerp5a=zero ............ a=zeroor3 + 4b = zero4b = -3 ............ b=-3/4
20ab -8a squared = 12
The GCF is 4ab.
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
The expression (-4ad - 8bc) cannot be simplified further without additional information about the variables (a), (b), (c), and (d). It represents a linear combination of the terms (-4ad) and (-8bc). If you need a specific evaluation, values for the variables must be provided.
8bc
5a2 - 20ab - 25b2 = 5(a2 - 4ab - 5b2) = 5(a2 - 4ba - 5b2) since -5b*b = -5b2 and -5b + b = -4b, then = 5(a - 5b)(a + b)
In step 4 of the special products section, the basic formula is given. It can also be found in most algebra books. (5a+4b)(25a2-20ab+16b2)
30, because their was no year zero
The earliest known example is from ancient Greece, around 8BC. However, it is likely socks date back to prehistory because having wet feet is really terrible.
The earliest known example is from ancient Greece, around 8BC. However, it is likely socks date back to prehistory because having wet feet is really terrible.
Gaius Maecenas (70BC-8BC) was a rich and powerful Roman and close colleague of Octavian, who became Emperor Augustus. His is best remembered for sponsoring the arts and was patron (financial supporter) of many of the "Augustan" poets.