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l=2*w+2 Perimeter P=2*l+2*w = 2(2w+2)+2w = 4w+4+2w = 6w+4 = 64 meters 6w=60 meters w=10 meters l=2*w+2 = 2*10+2 = 22 meters
L + W = 11 so L = 11 - W; L = 2W + 2; so 11 - W = 2W + 2 add W to each side: 11 = 3W + 2 subtract 2 from each side: 9 = 3W divide each side by 3: W = 3 so L = 8 m
length = w + 3area = 108area = w * (w + 3)108 = w^2 +3ww^2 + 3w -108 = 0w = 9 or -12The width is 9 meters, the length is 12 meters.
use pythagorean theorem where a2+b2=c2 (w+2)2+w2=102 2w2+4x+4=100 2w2+4x-96=0 divide by 2 w2 +2x-96=0 factor it (w-6)(w+8)0 you're answer is 6 centimeters because it can't be negative lol i posted this question and then figured it out :D
Given: 2w + 2l = 34 l = w + 2 Then: 2w + 2(w + 2) = 34 4w = 30 w = 7.5 l = 9.5
A = L x W 20 = 10 x W 20/10 = W 2 = W
l=2*w+2 Perimeter P=2*l+2*w = 2(2w+2)+2w = 4w+4+2w = 6w+4 = 64 meters 6w=60 meters w=10 meters l=2*w+2 = 2*10+2 = 22 meters
The cube has 6 faces. Area of the 6 faces = (6 x 200 x 200) = 240,000 square centimeters = 24 square meters Volume = L W H = (200 x 200 x 200) = 8,000,000 cubic centimeters = 8 cubic meters ============================================== Easier way to do it: 200 cm = 2 meters Area of one face = 2 x 2 = 4 square meters Area of 6 faces = 6 x 4 = 24 square meters Volume = 2 x 2 x 2 = 8 cubic meters
The area is L * W = 82.25 * 40.5 = 3331.125 sq cm The perimeter is 2(L + w) = 2 * (82.25 + 40.5) = 2 * 122.75 = 245.5 cm
L + W = 11 so L = 11 - W; L = 2W + 2; so 11 - W = 2W + 2 add W to each side: 11 = 3W + 2 subtract 2 from each side: 9 = 3W divide each side by 3: W = 3 so L = 8 m
Assume the room is rectangular. If the width is w then the length is w + 1. The perimeter is 2w + 2(w + 1) = 4w + 2. 4w + 2 = 14 : 4w = 12 : w = 3 meters
The dimensions of this rectangle are that its length is equal to 16 centimeters and its width is equal to 9 centimeters. To find these answers, you need to solve for two unknowns L and W in the equations L- W is equal to 7 and 2 x L plus 2 x W is equal to 50, where L is length and W is width.
length = w + 3area = 108area = w * (w + 3)108 = w^2 +3ww^2 + 3w -108 = 0w = 9 or -12The width is 9 meters, the length is 12 meters.
use pythagorean theorem where a2+b2=c2 (w+2)2+w2=102 2w2+4x+4=100 2w2+4x-96=0 divide by 2 w2 +2x-96=0 factor it (w-6)(w+8)0 you're answer is 6 centimeters because it can't be negative lol i posted this question and then figured it out :D
if width is equal to W and length is equal to L, then W x L = 80 L = W +2 so W x (W+2) = 80 solve to find W=8 and L= 10
Let x be L, so W = x - 2 P = 2(L + W) substitute 28 for P, x for L, and x - 2 for W; 28 = 2(x + x - 2) divide by 2 to both sides; 14 = 2x - 2 divide by 2 to both sides; 7 = x - 1 add 1 to both sides; 8 = x x - 2 = 8 - 2 = 6 So L = 8 cm and W = 6 cm. A = LW = 8 x 6 = 48 Thus the area is 48 cm^2
The number (w +W)/2. To find a halfway point (which is also the average), add the numbers together and divide by 2.