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The perimeter of a rectangle is 64m The length is 2 m more then twice the widthfind the dimensions?
l=2*w+2 Perimeter P=2*l+2*w = 2(2w+2)+2w = 4w+4+2w = 6w+4 = 64 meters 6w=60 meters w=10 meters l=2*w+2 = 2*10+2 = 22 meters
The perimeter of a rectangle is twice the the sum of its length and its width the perimeter is 22 meters and its length is two meters more than twice its width what is its length?
L + W = 11 so L = 11 - W; L = 2W + 2; so 11 - W = 2W + 2 add W to each side: 11 = 3W + 2 subtract 2 from each side: 9 = 3W divide each side by 3: W = 3 so L = 8 m
A wrestling mat is 3 meters longer than it is wide The mat covers a total of 108 square meters of floor area What is the length of the wrestling mat?
length = w + 3area = 108area = w * (w + 3)108 = w^2 +3ww^2 + 3w -108 = 0w = 9 or -12The width is 9 meters, the length is 12 meters.
What is the width of the rectangle in centimeters if it has a diagonal that measures 10 centimeters and a length that is 2 centimeters longer than the width?
use pythagorean theorem where a2+b2=c2 (w+2)2+w2=102 2w2+4x+4=100 2w2+4x-96=0 divide by 2 w2 +2x-96=0 factor it (w-6)(w+8)0 you're answer is 6 centimeters because it can't be negative lol i posted this question and then figured it out :D
The perimeter of a rectangle is twice the sum of its length and its width the perimeter is 34 meters and its length is 2 meters more than twice its width what is its length?
Given: 2w + 2l = 34 l = w + 2 Then: 2w + 2(w + 2) = 34 4w = 30 w = 7.5 l = 9.5
What is the width of a rectangle if the area is 20 square centimeters and the length is 10 centimeters?
A = L x W 20 = 10 x W 20/10 = W 2 = W
The perimeter of a rectangle is 64m The length is 2 m more then twice the widthfind the dimensions?
l=2*w+2 Perimeter P=2*l+2*w = 2(2w+2)+2w = 4w+4+2w = 6w+4 = 64 meters 6w=60 meters w=10 meters l=2*w+2 = 2*10+2 = 22 meters
What is the surface area and volume of a cube 200 cm?
The cube has 6 faces. Area of the 6 faces = (6 x 200 x 200) = 240,000 square centimeters = 24 square meters Volume = L W H = (200 x 200 x 200) = 8,000,000 cubic centimeters = 8 cubic meters ============================================== Easier way to do it: 200 cm = 2 meters Area of one face = 2 x 2 = 4 square meters Area of 6 faces = 6 x 4 = 24 square meters Volume = 2 x 2 x 2 = 8 cubic meters
What is the answer of a parallelogram with sides 82.25 centimeters and 40.5 centimeters?
The area is L * W = 82.25 * 40.5 = 3331.125 sq cm The perimeter is 2(L + w) = 2 * (82.25 + 40.5) = 2 * 122.75 = 245.5 cm
The perimeter of a rectangle is twice the the sum of its length and its width the perimeter is 22 meters and its length is two meters more than twice its width what is its length?
L + W = 11 so L = 11 - W; L = 2W + 2; so 11 - W = 2W + 2 add W to each side: 11 = 3W + 2 subtract 2 from each side: 9 = 3W divide each side by 3: W = 3 so L = 8 m
The room is 1 meter longer than it is wide it's perimeter is 14 meters Find the width in meters?
Assume the room is rectangular. If the width is w then the length is w + 1. The perimeter is 2w + 2(w + 1) = 4w + 2. 4w + 2 = 14 : 4w = 12 : w = 3 meters
The difference between the length and width of a rectangle is 7 centimeters Find the dimensions of the rectangle if its perimeter is 50 centimeters?
The dimensions of this rectangle are that its length is equal to 16 centimeters and its width is equal to 9 centimeters. To find these answers, you need to solve for two unknowns L and W in the equations L- W is equal to 7 and 2 x L plus 2 x W is equal to 50, where L is length and W is width.
A wrestling mat is 3 meters longer than it is wide The mat covers a total of 108 square meters of floor area What is the length of the wrestling mat?
length = w + 3area = 108area = w * (w + 3)108 = w^2 +3ww^2 + 3w -108 = 0w = 9 or -12The width is 9 meters, the length is 12 meters.
What is the perimeter of a rectangle with a length of 15 centimeters and with of 10 centimeters?
The perimeter of a rectangle is calculated by adding up the lengths of all its sides. In this case, the length is 15 centimeters and the width is 10 centimeters. To find the perimeter, you would add up all four sides: 15 cm + 10 cm + 15 cm + 10 cm = 50 cm. Therefore, the perimeter of the rectangle is 50 centimeters.
What is the width of the rectangle in centimeters if it has a diagonal that measures 10 centimeters and a length that is 2 centimeters longer than the width?
use pythagorean theorem where a2+b2=c2 (w+2)2+w2=102 2w2+4x+4=100 2w2+4x-96=0 divide by 2 w2 +2x-96=0 factor it (w-6)(w+8)0 you're answer is 6 centimeters because it can't be negative lol i posted this question and then figured it out :D
The length of a rectangle is 2 meters more than its width The area of the rectangle is 80 square meters What is the length and width of the rectangle?
if width is equal to W and length is equal to L, then W x L = 80 L = W +2 so W x (W+2) = 80 solve to find W=8 and L= 10
A rectangle has a perimeter of 28 centimeters The width of the rectangle is 2 centimeters less than the length What is the area of the rectangle?
Let x be L, so W = x - 2 P = 2(L + W) substitute 28 for P, x for L, and x - 2 for W; 28 = 2(x + x - 2) divide by 2 to both sides; 14 = 2x - 2 divide by 2 to both sides; 7 = x - 1 add 1 to both sides; 8 = x x - 2 = 8 - 2 = 6 So L = 8 cm and W = 6 cm. A = LW = 8 x 6 = 48 Thus the area is 48 cm^2
