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The perimeter of a rectangle is 64m The length is 2 m more then twice the widthfind the dimensions?
l=2*w+2 Perimeter P=2*l+2*w = 2(2w+2)+2w = 4w+4+2w = 6w+4 = 64 meters 6w=60 meters w=10 meters l=2*w+2 = 2*10+2 = 22 meters
The perimeter of a rectangle is twice the the sum of its length and its width the perimeter is 22 meters and its length is two meters more than twice its width what is its length?
L + W = 11 so L = 11 - W; L = 2W + 2; so 11 - W = 2W + 2 add W to each side: 11 = 3W + 2 subtract 2 from each side: 9 = 3W divide each side by 3: W = 3 so L = 8 m
A wrestling mat is 3 meters longer than it is wide The mat covers a total of 108 square meters of floor area What is the length of the wrestling mat?
length = w + 3area = 108area = w * (w + 3)108 = w^2 +3ww^2 + 3w -108 = 0w = 9 or -12The width is 9 meters, the length is 12 meters.
What is the width of the rectangle in centimeters if it has a diagonal that measures 10 centimeters and a length that is 2 centimeters longer than the width?
use pythagorean theorem where a2+b2=c2 (w+2)2+w2=102 2w2+4x+4=100 2w2+4x-96=0 divide by 2 w2 +2x-96=0 factor it (w-6)(w+8)0 you're answer is 6 centimeters because it can't be negative lol i posted this question and then figured it out :D
The perimeter of a rectangle is twice the sum of its length and its width the perimeter is 34 meters and its length is 2 meters more than twice its width what is its length?
Given: 2w + 2l = 34 l = w + 2 Then: 2w + 2(w + 2) = 34 4w = 30 w = 7.5 l = 9.5
