the answer is EE because A is 1 and B is 2 so 12, and D is 4, C is 3. So it ends up as 43 plus 12, which is EE because E is 5 so It would say 55.
Commutativity.
If, as is normal, ab represents a times b, etc then ab + ab + cc = 2ab + c2 which is generally not the same as abc.
ab + 2
ab=1a+1b a is equal to either 0 or two, and b is equal to a
dc = 73.91261929 feet. 72
a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)
yes because ab plus bc is ac
No - a pos can not donate blood to a negative
Commutativity.
2ab
then the baby will be O plus, or AB plus , I think .
If, as is normal, ab represents a times b, etc then ab + ab + cc = 2ab + c2 which is generally not the same as abc.
associative property
AB pos or AB neg
10!
No. A times B = AB
ab + 2