a^(3) + a^(2) Factors to a^(2) [ a^(2) + 1 ] NB THe terms in the square brackets do NOT factor. Reason, Any ywo squared terms with a positive (+) between then does NOT factor Think of a^(2) + 1 as a^(2) + 1^(2) . A pair of squared terms with a negative between them DOES factor. So if you initial expression was a^(4) - a^(2) Then a^(2) [ a^(2) - 1^(2)] a^(2)[a - 1)(a + 1) Fully factored. Note the two different signs.
(a2 + a + a2) = (2a2 + a) = a (2a + 1)
a2 - 4a + 4
a2 + -5a2 - a2 - a = a2 - 5a2 - a2 - a = a2 - 6a2 - a = -5a2 - a
a2 + a2 = 2a2
a2+9a+20 = (a+4)(a+5) when factored
a2+2a2b+2ab2+b2
5 - a - 1 + c - 6a2 + a2
A42a
22
a2
5a+3a2a2= 8a a2