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Which polygon has no of sides equal to diagonal?
The formula for the number of diagonals in a polygon is s*(s-1)/2 - s To find such a polygon, we solve for when that formula equals s s*(s-1)/2 - s = s s*(s-1)/2 = 2s (s-1)/2 = 2 s-1 = 4 s = 5 Thus, the polygon with this property is the pentagon.
Formula of radious given curve length and chord length?
R = radius c = chord length s = curve length c = 2Rsin(s/2R) you can solve for radius by trial and error as this is a transcendental equation
What is the equation of the line of symmetry?
7-8=d-s
What is the formula for finding the area of a square?
A=s^2 or A=s*s A is the area, and s is a side.
If the diameter of a rectangle is 10 meters and one side is 2 meters larger than another then what are the lengths of the sides?
In a rectangle there are two sets of lines - those opposite each other are the same length. So the phrasing of this question tells us that the two longest sides are 2 metres longer than the short sides, and that all the sides add up to 10 metres. So, if we call the short sides S, then 2S + 2(S+2) = 10 This works out to 2S + 2S + 4 = 10 This reduces to 4S = 6 And that gives us S = 6/4 So S = 1.5 So now we know that the short sides are both 1.5 metres and the long sides are both 3.5 metres Adding these together we get 1.5 + 1.5 + 3.5 + 3.5 = 10
What is the perpendicular bisector equation joining the points of s 2s and 3s 8s on the Cartesian plane showing work?
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
2r plus 2s equals 50 and 2r minus s equals 17?
2r + 2s = 50 2r - s = 17 therefore 4r - 2s = 34 Add so that you can eliminate one of the variables: 2r + 2s = 50 4r - 2s = 34 ---------------- 6r + 0s = 84 Solve for r: 6r = 84 r = 14 Substitute r into one of the original equations: 2(14) + 2s = 50 28 + 2s = 50 2s = 22 s = 11 Doublecheck with the other original equation: 2(14) - 11 = 28 - 11 = 17
What is 4s plus 10 equals 2s plus 2?
It is a simple linear equation in 's'. Its solution is the number that 's' must bein order to make it a true statement. The solution may be found like this:4s + 10 = 2s + 2Subtract 10 from each side of the equation:4s = 2s - 8Subtract 2s from each side:2s = -8Divide each side by 2 :s = -4
What is the value of s in the equation 4(2s 1) 7s 12?
If you mean: 4(2s-1) = 7s+12 then the value of s works out as 16
Solve for s 6s plus 2s equals 72?
6s+2s=72 combine like terms 6s+2s=8s set equal to 72 8s=72 divide both sides by 8 to solve for "s". 8s=72 8 8 your answer is s= 72/8 which is 9.
How do you simplify s plus t plus s?
If you simplify the equation (s+t+s) the answer is 2s+t
What is 2s plus 17 equals 2s plus 17?
2s + 17 = 2s + 17 1) First, you want to start on the left side of the equation and subtract 17 from both sides. 2s = 2s 2) Then, you take the 2 on the left side and divide it on both sides. s = s 3) You are left with s (Or 1s) on both sides, so s = 1.
What is the perpendicular bisector equation of a line joined by the points of s 2s and 3s 8s showing key stages of work?
It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0
What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?
Endpoints: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope of line: 3/1 Slope of perpendicular line: -1/3 Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
What is the perpendicular bisector equation of the line whose end points are at s 2s and 3s 8s on the Cartesian plane?
Points: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular equation: y -5s = -1/3(x -2s) => 3y = -x +17s Perpendicular bisector equation in its general form: x +3y -17s = 0
What is the perpendicular bisector equation of the line joined by the points of s 2s and 3s 8s?
Points: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular equation: y-5s = -1/3(x-2s) => 3y-15s = -x+2s => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
What is in its general form the perpendicular bisector equation meeting the line segment of s 2s and 3s 8s at its midpoint?
Points: (s, 2s) and (3s, 8s) Slope: 3 Perpendicular slope: -1/3 Midpoint: (2s, 5s) Equation in its general form: x+3y-17 = 0
