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p q and p q cannot be a useful part of a system of simultaneous equations since they are the same!

Q: What is p q and p q as a simultaneous equation?

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2 Pints in a Quart

If the solutions are p and q, then the quadratic is (x-p)(x-q) = 0 or x2 - (p+q)x + pq = 0 Hope this is what the question meant!

Two ratios, p/q and r/s (q and s non-zero) are equal if p/q - r/s = 0.

If the two axes intersect at the point (p, q), then the equation is: (x -p)2/25 + (y - q)2/9 = 1

p and q

Related questions

If (p, q) is any point on the line, then the point slope equation is: (y - q)/(x - p) = 2 or (y - q) = 2*(x - p)

2 Pints in a Quart

Assume the two numbers are P & Q, the equation is P + Q = 53, rearranging this gives Q = 53 - P

If P varies directly with the square of Q then the equation would be in the form of P = kQ2, where k is the constant of variation so the new equation would be: P = 6Q2, so when Q = 12 we have P=6*122, or P = 864

If the solutions are p and q, then the quadratic is (x-p)(x-q) = 0 or x2 - (p+q)x + pq = 0 Hope this is what the question meant!

the frequently of the heterozygous dominant genotype

Two ratios, p/q and r/s (q and s non-zero) are equal if p/q - r/s = 0.

If the two axes intersect at the point (p, q), then the equation is: (x -p)2/25 + (y - q)2/9 = 1

A simultaneous equation

p and q

Unless it's something weird, then: p*(-8)+q... There's really nothing else to do with it since it's an expression and not an equation.

The values of p and q work out as -2 and 4 respectively thus complying with the given conditions.