p q and p q cannot be a useful part of a system of simultaneous equations since they are the same!
If the two axes intersect at the point (p, q), then the equation is: (x -p)2/25 + (y - q)2/9 = 1
The values of p and q work out as -2 and 4 respectively thus complying with the given conditions.
The Bernoulli equation was formulated by Daniel Bernoulli who was a Swiss mathematician. The Bernoulli equation is basically a statement of the conservation of energy in fluid dynamics.
2=p in a q
If (p, q) is any point on the line, then the point slope equation is: (y - q)/(x - p) = 2 or (y - q) = 2*(x - p)
The p and q variables in the Hardy-Weinberg equation represent the frequencies of the two alleles in a population. The equation is often written as p^2 + 2pq + q^2 = 1, where p and q represent the frequencies of the dominant and recessive alleles, respectively.
p q and p q cannot be a useful part of a system of simultaneous equations since they are the same!
2 = Pints in a Quart
If the two axes intersect at the point (p, q), then the equation is: (x -p)2/25 + (y - q)2/9 = 1
The values of p and q work out as -2 and 4 respectively thus complying with the given conditions.
The Bernoulli equation was formulated by Daniel Bernoulli who was a Swiss mathematician. The Bernoulli equation is basically a statement of the conservation of energy in fluid dynamics.
2p + 3q = 13, 5p - 4q = -2 Multiply the first equation by 4 and the second by 3 and add them, which gets rid of the q: 8p + 15p = 52 - 6, and 23p = 46, so p=2. Plug that into the first equation to find q: 4 + 3q = 13, so q=3. Test your answers in the second equation to be sure: 5(2) - 4(3) = 10-12 = -2. It checks. So p=2, q=3.
2 P in a Q ' Two persons in a queue.
If p = 50 of q then q is 2% of p.
2=p in a q
I think you mean the roots are prime numbers. Let the two roots be primes p and q Then the equation factorises to (x - p)(x - q) = 0 which can be expanded to give: x² - (p + q)x + pq = 0 Which comparing coefficients of the original gives: a = p + q 2b = pq as b is an integer, pq must be even, → at least one of p or q must be even → as they are both primes and at least one is even, it MUST be 2 as 2 is the ONLY even prime Assume p is an even prime, ie p = 2 → a = 2 + q 2b = 2q → b = q → a - b = (2 + q) - q = 2 (It doesn't matter if the other prime is even (2) or not as it cancels out from a - b.)