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Q: What is the 21st term in this sequence 18 23 28 33 38?

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The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

58

All you have to do is add 5 each time(x+5) It's 43

Since the terms of the given sequence differ by different numbers, then the terms would start a new pattern, so that the other term of the sequence is 23.16 26 21 13 23 18 10...

Every next number is increased by 5. The next number in the sequence is 23.

41

33332344444

Arithmetic- the number increases by 10 every term.

8, 13, 18, 23, 28, etc.

the equation that defines this sequence is nx = (n+(7+4(x-1))) (where x is the position of the term in the sequence (that is position 1 is 12, position 2 is 23 etc..)

20, 21, 22, 23, 24, 25, 26, 27, 28, 29

3/23

every next term is 4 smaller than previous so 7th term = -23

22

It is: 27-2n

5, 11, 17, 23, 29

It is: 5n+3 and so the next term is 28

The nth term is 3(n+1). The twenty-third term is equal to 3 x (23 + 1) = 72

The next number is 47. Each term is 1 more than double the term before it.

By figuring out the rule on which the sequence is based. I am pretty sure the last number is supposed to be 125 - in that case, this is the sequence of cubic numbers: 13, 23, 33, etc.

Well, judging by the sequence of numbers, the pattern would be to subtract one more than the last time from each new number. Meaning 33-1=32 then 32-2=30 then 30-3=27. The next three numbers would be 27-4=23 and 23-5=18 and finally 18-6=12. So 23 18 and 12 would be the next three numbers in sequence.