The sequence 3, 8, 13, 18, 23, 28 increases by 5 each time. This indicates a linear pattern. The nth term can be expressed as ( a_n = 3 + 5(n - 1) ), which simplifies to ( a_n = 5n - 2 ). Thus, the nth term of the sequence is ( 5n - 2 ).
The 'n'th term is [ 13 + 5n ].
To find the nth term of the sequence 3, 8, 13, 18, I first identified the pattern in the differences between consecutive terms: 5, 5, 5. Since these differences are constant, the sequence is linear. The nth term can be expressed in the form ( a_n = an + b ). By using the first term (3) and the common difference (5), I derived the formula: ( a_n = 5n - 2 ).
Well, it would depend what the sequence was...? If the sequence was 2,4,6,8,10,12,14,16,18,20, then the 9th term would be 18!
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To find the nth term of the sequence 4, 10, 18, 28, 40, we first identify the pattern in the differences between consecutive terms: 6, 8, 10, and 12. The second differences are constant at 2, indicating a quadratic sequence. The nth term can be expressed as ( a_n = n^2 + n + 2 ). Thus, the nth term of the sequence is ( n^2 + n + 2 ).
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
To find the nth term of the sequence 3, 8, 13, 18, I first identified the pattern in the differences between consecutive terms: 5, 5, 5. Since these differences are constant, the sequence is linear. The nth term can be expressed in the form ( a_n = an + b ). By using the first term (3) and the common difference (5), I derived the formula: ( a_n = 5n - 2 ).
Well, it would depend what the sequence was...? If the sequence was 2,4,6,8,10,12,14,16,18,20, then the 9th term would be 18!
To find the nth term of a sequence, we first need to identify the pattern or rule that governs the sequence. In this case, the sequence is decreasing by 6 each time. Therefore, the nth term can be represented by the formula: 18 - 6(n-1), where n is the position of the term in the sequence.
The sequence 18, 27, 36, 45, 54 is an arithmetic sequence where each term increases by 9. To find the nth term, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term (18) and ( d ) is the common difference (9). Thus, the nth term is ( a_n = 18 + (n-1) \times 9 = 9n + 9 ).
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
The nth term of the sequence is (n + 1)2 + 2.
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
18,23,28,33,... #1 is 18 #2 is 23 A difference of '5' Hence we can write '5n + x = 18 Where 'n' equals '1' Hence 5(1) + x = 18 5 + x = 18 Hence x = 18 - 5 = 13 So nth term is 5n + 13 NB Verification; does it work for the 4th term 5(4)+ 13 = 20 + 13 = 33 Which is true from above list.
Un = 5n - 2