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What else can I help you with?
Factor ac plus ad plus bc plus bd?
a(c+d)+b(c+d)=(a+b)(c+d)
How is a plus b over a minus b equals c plus d over c minus d?
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
Can AC plus AD plus BC plus BD can be factored as (A plus C)(B plus D)?
Yes, the expression AC + AD + BC + BD can be factored as (A + C)(B + D). This is evident by applying the distributive property, where expanding (A + C)(B + D) yields AB + AD + BC + CD. The terms AC and BD are not present, so the expression can be expressed in a different form, but the original expression itself represents a different factoring structure.
What is BC' plus BC' simplified?
BC' + BC' = 2BC'
What mathematical property is a plus bc bc plus a?
It is the property of commutativity.
If ab plus bc equals ac then ac equals ab plus bc?
yes because ab plus bc is ac
5a plus d - bc equals a equals 5 b equals 7 c equals 2 d equals 4 what is the correct answer?
4
Ab plus bc equals bc plus ab what property is this?
Commutativity.
If a over b equals c over d then is it possible that a plus b equals c plus d If not then give Mathematical Reason for that?
a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)
What does a over b plus c over d equal?
The expression ( \frac{a}{b} + \frac{c}{d} ) can be combined by finding a common denominator. The result is ( \frac{ad + bc}{bd} ). Thus, ( \frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd} ).
Bela bartok church mode music?
* dorian - d ef g a bc d * phrygian -ef g a bc d e* lydian - f g a bc d ef* mixolydian - g a bc d ef g
1 plus x equals b c plus x equals d d plus x equals 89 b plus x equals c d equals?
1+x=dd+x so dd=1 so d=1 1+x=89b+x so 89b=1 so b=1/89 bc+x=1+x so bc=1 so c=1/(1/89) = 89 so cd=89 (and x=88)
