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That expression has no answer, simply because it's not a question.

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12y ago

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Factor ac plus ad plus bc plus bd?

a(c+d)+b(c+d)=(a+b)(c+d)


How is a plus b over a minus b equals c plus d over c minus d?

(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c


What is BC' plus BC' simplified?

BC' + BC' = 2BC'


What mathematical property is a plus bc bc plus a?

It is the property of commutativity.


If ab plus bc equals ac then ac equals ab plus bc?

yes because ab plus bc is ac


Ab plus bc equals bc plus ab what property is this?

Commutativity.


5a plus d - bc equals a equals 5 b equals 7 c equals 2 d equals 4 what is the correct answer?

4


If a over b equals c over d then is it possible that a plus b equals c plus d If not then give Mathematical Reason for that?

a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)


Bela bartok church mode music?

* dorian - d ef g a bc d * phrygian -ef g a bc d e* lydian - f g a bc d ef* mixolydian - g a bc d ef g


1 plus x equals b c plus x equals d d plus x equals 89 b plus x equals c d equals?

1+x=dd+x so dd=1 so d=1 1+x=89b+x so 89b=1 so b=1/89 bc+x=1+x so bc=1 so c=1/(1/89) = 89 so cd=89 (and x=88)


What do you do after cross multiplying when comparing fractions with unlike denominators?

Suppose the two fractions are a/b and c/d ad that b, d > 0. Then cross multiplication gives ad and bc. If ad > bc then a/b > c/d, If ad = bc then a/b = c/d, and If ad < bc then a/b < c/d


What does 447 bc plus 15 years later equal?

432 BC.