False.
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
no because to be divisible by 9 the number has to equal 9 for instance 2+9+3+8=22 so it is not divisible by 9. But 32121 3+2+1+2+1=9 so it is divisible by 9
The numbers 2, 3, and 9 are all divisible by 1.
1, 2, 7, 3 and 6 are not divisible by 4 and/or 9. 12736 is divisible by 4 but not by 9.
not divisible by 9.but it is divisible by 4.
1262 is even, so 1262 is divisible by 2. 1 + 2 + 6 + 2 = 11 which is not divisible by 3 nor 9, so 1262 is not divisible by 3 nor 9.
It is divisible only by 3; It is not divisible by 2, 4, 5, 6, 9, 10. 17211 is odd, so not divisible by 2, 4, 6 nor 10. 1 + 7 + 2 + 1 + 1 = 12 which is divisible by 3, so 17211 is divisible by 3, but 12 is not divisible by 9, so 17211 is not divisible by 9. 17211 does not end in 5 or 0 so not divisible by 5
yes. 2 + 1 + 6 = 9 9 is divisible by 3 so 216 is divisible by 3.
You can determine if any number is divisible by nine by adding its digits together: 2 + 1 + 2 +4 = 9 if the result is divisible by 9, then the original number is divisible by 9. In this case, the answer is divisible by 9 so, yes it is (in fact it is 236 x 9).
To determine if a number is divisible by 9, you need to add up all the digits in the number. In this case, 2 + 4 + 1 + 1 + 1 = 9. Since the sum of the digits is divisible by 9, the number 24111 is also divisible by 9.
If you add the digits in any given number and they add up to 9, then that number is divisible by nine. Example: 72 = 7 + 2 = 9, therefore its divisible by 9 Example: 2034 = 2 + 0 + 3 + 4 = 9, therefore it's divisible by nine as well. Example: 111123 = 1+1+1+1+2+3 = 9, therefore it is divisible by 9, too.
1, 2, 0, 3 and 8 are not divisible by 4 and/or 9. Neither is 12038.