False.
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
no because to be divisible by 9 the number has to equal 9 for instance 2+9+3+8=22 so it is not divisible by 9. But 32121 3+2+1+2+1=9 so it is divisible by 9
The numbers 2, 3, and 9 are all divisible by 1.
1, 2, 7, 3 and 6 are not divisible by 4 and/or 9. 12736 is divisible by 4 but not by 9.
not divisible by 9.but it is divisible by 4.
1262 is even, so 1262 is divisible by 2. 1 + 2 + 6 + 2 = 11 which is not divisible by 3 nor 9, so 1262 is not divisible by 3 nor 9.
It is divisible only by 3; It is not divisible by 2, 4, 5, 6, 9, 10. 17211 is odd, so not divisible by 2, 4, 6 nor 10. 1 + 7 + 2 + 1 + 1 = 12 which is divisible by 3, so 17211 is divisible by 3, but 12 is not divisible by 9, so 17211 is not divisible by 9. 17211 does not end in 5 or 0 so not divisible by 5
yes. 2 + 1 + 6 = 9 9 is divisible by 3 so 216 is divisible by 3.
You can determine if any number is divisible by nine by adding its digits together: 2 + 1 + 2 +4 = 9 if the result is divisible by 9, then the original number is divisible by 9. In this case, the answer is divisible by 9 so, yes it is (in fact it is 236 x 9).
If you add the digits in any given number and they add up to 9, then that number is divisible by nine. Example: 72 = 7 + 2 = 9, therefore its divisible by 9 Example: 2034 = 2 + 0 + 3 + 4 = 9, therefore it's divisible by nine as well. Example: 111123 = 1+1+1+1+2+3 = 9, therefore it is divisible by 9, too.
To determine if a number is divisible by 9, you need to add up all the digits in the number. In this case, 2 + 4 + 1 + 1 + 1 = 9. Since the sum of the digits is divisible by 9, the number 24111 is also divisible by 9.
1, 2, 0, 3 and 8 are not divisible by 4 and/or 9. Neither is 12038.