0
Want this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
How do you expand cd-ab if the entire expression is in parentheses and squared?
(CD - ab)^2 = (CD - ab)(CD - ab) = c^2 d^2 - 2abcd + a^2b^2 Try it with say a = 4, b = 3, c = 2 & d = 1: Then CD = 2 and ab = 12 so CD - ab = -10 and squared = 100 c^2 = 4 d^2 = 1 so c^2d^2 = 4 x 1 = 4 a^2 = 16 b^2 = 9 so a^2b^2 = 16 x 9 =144 2abcd = 48 giving 4 - 48 + 144 = 100. Shazam!
How do you draw a triangle with an area of 5 square units?
== == 1) Draw a line segment AB of 5 units 2) Draw the perpendicular bisector CD of AB such that Cd meerts AB at C. 3) Mark off CE = 2 units on CD 4) Draw the straight line segments AE & BE. ABE is your triangle. Its base (AB) = 5 and height (CE) = 2, so its area = [base x ht] / 2 = 5 sq units
Slope of a line AB is 4 what is the slope of CD if CD is perpendicular to AB?
Slope of perpendicular line is the negative reciprocal. So it is -1/4
Where does point AB intersects CD?
You need to provide more information in order to answer this question. However, you need to use either Subsitution or Elimination. Substitue the equation of Line AB into the equation of Line CD. E.g. Line AB y=2x Line CD y=3x+2 2x=3x+2 3x-2x=-2 x=-2 Sub x=-2 into either equation y=2(-2) y=-4 Therefore, the point of intersection is (-2, -4).
What is the measure of a secant CD If ab is 14 and bd is 4?
18
How do you expand cd-ab if the entire expression is in parentheses and squared?
(CD - ab)^2 = (CD - ab)(CD - ab) = c^2 d^2 - 2abcd + a^2b^2 Try it with say a = 4, b = 3, c = 2 & d = 1: Then CD = 2 and ab = 12 so CD - ab = -10 and squared = 100 c^2 = 4 d^2 = 1 so c^2d^2 = 4 x 1 = 4 a^2 = 16 b^2 = 9 so a^2b^2 = 16 x 9 =144 2abcd = 48 giving 4 - 48 + 144 = 100. Shazam!
plot the given points in a coordinate plane. Then determine whether the line segments named are congruent. 1 A(0, 1), B(4, 1), C(1, 2), D(1, 6); line AB and line CD?
we can create a graph with the x-axis representing the horizontal values and the y-axis representing the vertical values. let's determine whether the line segments AB and CD are congruent. The length of line segment AB can be calculated using the distance formula: AB = sqrt((x2 - x1)^2 + (y2 - y1)^2) For AB(0, 1) and CD(4, 1), the length of AB is: AB = sqrt((4 - 0)^2 + (1 - 1)^2) = sqrt(16 + 0) = sqrt(16) = 4 For CD(1, 2) and CD(1, 6), the length of CD is: CD = sqrt((1 - 1)^2 + (6 - 2)^2) = sqrt(0 + 16) = sqrt(16) = 4 Since the length of AB is equal to the length of CD (both are 4 units), we can conclude that line segments AB and CD are congruent.
How do you draw a triangle with an area of 5 square units?
== == 1) Draw a line segment AB of 5 units 2) Draw the perpendicular bisector CD of AB such that Cd meerts AB at C. 3) Mark off CE = 2 units on CD 4) Draw the straight line segments AE & BE. ABE is your triangle. Its base (AB) = 5 and height (CE) = 2, so its area = [base x ht] / 2 = 5 sq units
Slope of a line AB is 4 what is the slope of CD if CD is perpendicular to AB?
Slope of perpendicular line is the negative reciprocal. So it is -1/4
Where does point AB intersects CD?
You need to provide more information in order to answer this question. However, you need to use either Subsitution or Elimination. Substitue the equation of Line AB into the equation of Line CD. E.g. Line AB y=2x Line CD y=3x+2 2x=3x+2 3x-2x=-2 x=-2 Sub x=-2 into either equation y=2(-2) y=-4 Therefore, the point of intersection is (-2, -4).
The diagonals of square abcd intersect at e if ae equals 2 find to perimeter of abcd?
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
How do you Factorise 4ab - 6ab?
4ab - 6ab = ab(4 - 6). ab(4 - 6) = 2ab(2-3)
What are the 4 main human blood types?
1. A 2. B 3. AB 4. O
What is the measure of a secant CD If ab is 14 and bd is 4?
18
Help need now Find to the nearest tenth the perimeter of a quadrilateral with vertices A 2 1 B7 3 C12 1 and D 7 -4 and what is shape's most discriptive name Please show work or expln?
A = (2, 1) B = (7, 3) Therefore, AB^2 = (7-2)^2 + (3-1)^2 = 25 + 4 = 29 and so AB = sqrt(29) units.You can find BC, CD, and DA similarly.You will find that AB = BC and CD = DA but that BC is not = CD.Therefore the shape is a kite (two pairs of adjacent sides equal).And perimeter = 2*sqrt(29) + 2*sqrt(50) = 24.9 units.
What is AB equals C plus D?
AB = 2 x 4 (8) C = 3 D = 5
What are the types of chemical reactions and how are they identified?
Typically there are 5 types of chemical reactions.(1) synthesis. A + B ==> AB (2) degradation/decomposition. AB ==> A + B (3) combustion. CH4 + 2O2 ==> CO2 + 2H2O (4) single replacement. A + BC ==> AC + B (5) double replacement. AB + CD ==> AD + CB
