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A rhombus has four equal sides and its diagonals bisect each other at right angles. The area of the rhombus ia given by following formula where x and y are the lengths of the diagonals of the rhombus...A=1/2xy. Example, the diagonals of a rhombus where x = 26 and y = 14....A=1/2xy...=1/2 x 26 x 14 which equals 182. so the area of the rhombus is 182 square inches, miles or whatever measurement you are dealing with the 3d annaloge to a rhombus is the rhomboid, the formula to fin dteh volume of that is A . (B x C).
Without knowing where a, b and h are, we have no way of knowing whether ab and ah are lengths, widths or diagonals and consequently, no way of determining the area.
1/2*(n2-3n) = diagonals when n equals number of sides.
ind the area of the rhombus if AE = 20 m and DE = 32 m.
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The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonalsIn your case, that's 14 x 17 / 2 = 119
Oh, dude, it's like the diagonals in a rhombus are totally those lines that connect the opposite corners. They're like the fancy crossroads of the rhombus world, making all those right angles and stuff. So yeah, if you ever need to find them, just look for those lines that cut the rhombus in half diagonally.
A rhombus has four equal sides and its diagonals bisect each other at right angles. The area of the rhombus ia given by following formula where x and y are the lengths of the diagonals of the rhombus...A=1/2xy. Example, the diagonals of a rhombus where x = 26 and y = 14....A=1/2xy...=1/2 x 26 x 14 which equals 182. so the area of the rhombus is 182 square inches, miles or whatever measurement you are dealing with the 3d annaloge to a rhombus is the rhomboid, the formula to fin dteh volume of that is A . (B x C).
The diagonals of a rhombus are always congruent. A rhombus is a quadrilateral with all sides of equal length. Due to its symmetry, the diagonals of a rhombus bisect each other at right angles, and they are always of the same length. This property distinguishes a rhombus from other quadrilaterals like rectangles or parallelograms.
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:Area = (1/2) * ( 12 * 7) = 42.The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)
half of two equals onehalf of two + three fifths = 1 3/5 = 1.6
1.5 tablespoons of water is 22.5 mls.
Without knowing where a, b and h are, we have no way of knowing whether ab and ah are lengths, widths or diagonals and consequently, no way of determining the area.
The diagonals of a rhombus are perpendicular to each other and bisect one another. So you can consider the diagonals dividing the rhombus into 4 identical, right-angled triangles where the sides subtending the right angle are of length 10/2 and 11/2. The area of each of these triangles is 1/2 * 10/2 * 11/2 = 110/8 There are 4 such triangles, so their combined area is 4 * 110 / 8 = 110 / 2 = 55 square units.
1/2*(n2-3n) = diagonals when n equals number of sides.