x2 + 8x + 16 describes a parabola, and as such does not have an area as it does not enclose any space.
It does however have a range. If you factor it, you can reduce it to (x + 4)2, which tells us that it has a range of 0 → ∞, with it's focal point being at (-4, 0).
X2 + 8x + 16 = 10x +16x2 + 8x + 16=2x + 8x + 16=10x + 16
x + 4
(x2 - x - 20) / (x2 + 8x + 16) = [(x - 5)(x + 4)] / (x + 4)2 = (x - 5) / (x + 4)
x2+8x+9 = -7 x2+8x+9+7 = 0 x2+8x+16 = 0 (x+4)(x+4) = 0 Therefore: x = -4 and also x = -4 (they both have equal roots)
x*x - 8x +16 = 0 x*x = 8x + 16 x - 16 = _/8x x_/-4 = 2 x = 2
x2 + 8x - 6 = 0 x2 + 8x + 16 = 22 (x + 4)2 = 22 x + 4 = ± √22 x = -4 ± √22
x2 + 8x - 5 = 0 ∴ x2 + 8x + 16 = 21 ∴ (x + 4)2 = 21 ∴ x + 4 = ± √21 ∴ x = -4 ± √21
(x-4)(x-4)
2 this Domo
x2 + 8x + 15 = (x + 3)(x + 5)
x2 + 8x + 15 = (x + 3) (x + 5).
x2 + 8x - 2 = 0 => x2 + 8x = 2 => x2 + 8x + 16 = 2 + 16 = 18 => (x + 4)2 = 18 => x + 4 = +or- sqrt(18) = +or- 3*sqrt(2) so x = -4 +or- 3*sqrt(2)