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Q: Who long is the other side of a rectangle if the width is 5cm and the diagonal 13?

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The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd

infinitely far

If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.

15 cm Solved through Pythagoras' theorem.

The diagonal is 14.21 cm

The diagonal is 15.652'

The diagonal is 221.2 inches long.

Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764

The diagonal would be 12.53 meters.

The diagonal is 100'

The diagonal is 47.707'

The diagonal is 48.877 feet.

The rectangle is a long width square. you

The diagonal is 22.203 centimeters.

The diagonal is 3.231 meters.

-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)

26.4 inches for the diagonal.

12.5cm

15 cm for the diagonal.

104.1 feet

157.6102789 inches

44 feet 4 inches

If a rectangle is 40 inches. the rectangle is 12 inches long then: 2 * 12 + 2 * width = 40 2 * width = 40 - 2*12 = 40 - 24 = 16 width = 16 / 2 = 8 So the width of the rectangle is 8.

According to the given length & width, the diagonal must be 15 cm.So,2X - 11 = 152X = 26X = 13

The diagonal creates a right angled triangle with one pair of long and short sides - the diagonal is the hypotenuse. We know the angle between the long side (adjacent) and hypotenuse as 42.6°; We want to find the length of the short (width) side (opposite). We can use the Tan ratio: tan = opposite/adjacent → opposite = adjacent × tan → width = 26.63 in × tan 42.6° = 24.487... in → width is 24.5 inches to the nearest tenth of an inch.