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How do you find a p value when given the focus and directrix?
To find the p-value for a parabola given its focus and directrix, first identify the coordinates of the focus (F) and the equation of the directrix (a line). The p-value represents the distance from the vertex of the parabola to the focus (or the vertex to the directrix), which is half the distance between them. Calculate this distance using the formula for distance between a point and a line, or by measuring the distance from the vertex to either the focus or the directrix. The p-value is then the absolute value of this distance.
What is a definition of a reflection of a point P across the axis to the point P?
The reflection of a point ( P ) across an axis (such as the x-axis or y-axis) results in a new point ( P' ) that is equidistant from the axis but on the opposite side. For example, if ( P ) is at coordinates ( (x, y) ), its reflection across the x-axis would be ( P' ) at ( (x, -y) ). The distance between ( P ) and the axis remains the same, ensuring that the two points are symmetrical with respect to that axis.
How you would find the distance from a point to a plane?
Let the point P have coordinates (p, q, r) and let the equation of the plane be ax + by +cz + d = 0Then the distance from the point to the plane is abs(ap + bq + cr) / sqrt(a^2 + b^2 + c^2).
How can you make two arrowheads and a rhombus out of a square?
Suppose the square is ABCD. Draw the diagonal AC.Mark one point on the diagonal, P (not the midpoint of AC), at a distance x from A. Mark another point, Q, also on the diagonal, at the same distance from C.Then,PBQD is a rhombus,ABPD and BCDQ are arrowheads.Suppose the square is ABCD. Draw the diagonal AC.Mark one point on the diagonal, P (not the midpoint of AC), at a distance x from A. Mark another point, Q, also on the diagonal, at the same distance from C.Then,PBQD is a rhombus,ABPD and BCDQ are arrowheads.Suppose the square is ABCD. Draw the diagonal AC.Mark one point on the diagonal, P (not the midpoint of AC), at a distance x from A. Mark another point, Q, also on the diagonal, at the same distance from C.Then,PBQD is a rhombus,ABPD and BCDQ are arrowheads.Suppose the square is ABCD. Draw the diagonal AC.Mark one point on the diagonal, P (not the midpoint of AC), at a distance x from A. Mark another point, Q, also on the diagonal, at the same distance from C.Then,PBQD is a rhombus,ABPD and BCDQ are arrowheads.
What is the image of C for a 180 and deg Counter clockwise rotation about P?
To find the image of point C after a 180-degree counterclockwise rotation about point P, you first identify the coordinates of both points. Then, you reflect point C across point P, effectively moving it to the opposite side of P at an equal distance. The resulting image will be directly opposite C in relation to P, forming a straight line through P.
How do you find a p value when given the focus and directrix?
To find the p-value for a parabola given its focus and directrix, first identify the coordinates of the focus (F) and the equation of the directrix (a line). The p-value represents the distance from the vertex of the parabola to the focus (or the vertex to the directrix), which is half the distance between them. Calculate this distance using the formula for distance between a point and a line, or by measuring the distance from the vertex to either the focus or the directrix. The p-value is then the absolute value of this distance.
What is a definition of a reflection of a point P across the axis to the point P?
The reflection of a point ( P ) across an axis (such as the x-axis or y-axis) results in a new point ( P' ) that is equidistant from the axis but on the opposite side. For example, if ( P ) is at coordinates ( (x, y) ), its reflection across the x-axis would be ( P' ) at ( (x, -y) ). The distance between ( P ) and the axis remains the same, ensuring that the two points are symmetrical with respect to that axis.
what- In the figure, what is the distance from point P to line a?
\sqrt(9.8)~ 3.13
In the figure, what is the distance from point P to line a?
3v/ 2 ~ 4.2
What jobs use heptagons?
It the UK the mint does: the British 50 pence and 20 p coins are both heptagonal.
How many nautical miles from Nassau to san juan p r?
The distance between the above places is approximately equal to 3421 nautical miles. To convert miles to nautical miles, multiply the miles by 0.86. This is point to point straight distance. The actual distance will change according to the route.
what- in the figure, what is the distance from point P o line a?
3v/ 2 ~ 4.2
How does the distance moved by an object between its starting point and its ending point compare with the displacement vector between the same point?
The distance moved by an object is the total length of the path traveled, while the displacement vector is the shortest distance between the starting and ending points in a straight line. Therefore, the distance moved can be greater than or equal to the displacement vector, depending on the path taken by the object.
Point G represents the location of the gym, and point P represents the location of the post office. Each unit on the grid represents one mile.Which of these is the distance between the gym and the post office?
6.7 mi
How you would find the distance from a point to a plane?
Let the point P have coordinates (p, q, r) and let the equation of the plane be ax + by +cz + d = 0Then the distance from the point to the plane is abs(ap + bq + cr) / sqrt(a^2 + b^2 + c^2).
How do you prove that a finite set of points cannot have any accumulation points in a complex analysis?
Complex analysis is a metric space so neighborhoods can be described as open balls. Proof follows a. Assume that the set has an accumulation point call it P. b. An accumulation point is defined as a point in which every neighborhood (open ball) around P contains a point in the set other than P. c. Since P is an accumulation point, I can choose an open ball around P that has a diameter less than the minimum distance between P and all elements of the finite set. Therefore there exists a neighbor hood around P which contains only P. Therefore P is not an accumulation point.
The distance between points P and Q is 8 units How many points are equidistant from P and Q and also 3 units from P?
zero Half the distance between them would be 4 units; so 3 units from P would not be close enough to Q to be equidistant.
