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What is the equation of a line that is perpendicular to 3y -x 9 and has a y-intercept of 6?
Wiki User
∙ 9y ago
If you mean: 3y=-x+9 then y=-1/3x+3 and the perpendicular equation is y=3x+6
Wiki User
∙ 9y ago
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What is the perpendicular bisector equation of the line whose endpoints are s 2s and 3s 8s?
Endpoints: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular bisector equation: 3y = -x+17s or as x+3y-17s = 0
What is the perpendicular bisector equation of the line joined by the points of s 2s and 3s 8s?
Points: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular equation: y-5s = -1/3(x-2s) => 3y-15s = -x+2s => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
What is the equation of a line that contains the point (21) and is perpendicular to the line y 3x 4?
If you mean the point of (2, 1) and the line y = 3x+4 Then the perpendicular slope is -1/3 and its equation works out as 3y = -x+5
What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?
Endpoints: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope of line: 3/1 Slope of perpendicular line: -1/3 Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
What is the equation and its perpendicular bisector equation of the line whose end points are at -2 3 and 1 -1 on the Cartesian plane?
Points: (-2, 3) and (1, -1) Midpoint: (-0.5, 1) Slope: -4/3 Perpendicular slope: 4/3 Equation: 3y = -4x+1 Perpendicular bisector equation: 4y = 3x+5.5
The equation of a line is x Minus 3y Plus 2 Equals 4. Which line is perpendicular to this line?
x-3y+2 = 4 -3y = -x+4-2 -3y = -x+2 y = 1/3x-2/3 Slope or gradient of the perpendicular line is -3 Use y-y1 = -3(x-x1) to find the perpendicular equation
What is the equation of the line that contains the point (21) and is perpendicular to the line y3x-4?
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
What is the equation of the line written in standard form that passes through the point (-3 4) and is perpendicular to the line 3x 2y5?
If you mean line of 3x+2y = 5 then y = -3/2x+2.5 Perpendicular slope: 2/3 Perpendicular equation: 3y = 2x+18 or as 2x-3y+18 = 0
What equation describes a line that passes through the point (-14) and is perpendicular to the line 4x-3y-9?
If you mean point (-1, 4) and equation of 4x-3y = -9 then y = 4/3x+3 Slope of equation: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13
What is the perpendicular bisector equation of the line whose endpoints are s 2s and 3s 8s?
Endpoints: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular bisector equation: 3y = -x+17s or as x+3y-17s = 0
What is perpendicular to the line 3x plus y equals 2?
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
What is the perpendicular bisector equation of the line joined by the points of s 2s and 3s 8s?
Points: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular equation: y-5s = -1/3(x-2s) => 3y-15s = -x+2s => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
What is the equation of a line that contains the point (21) and is perpendicular to the line y 3x 4?
If you mean the point of (2, 1) and the line y = 3x+4 Then the perpendicular slope is -1/3 and its equation works out as 3y = -x+5
What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?
Endpoints: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope of line: 3/1 Slope of perpendicular line: -1/3 Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
What is the equation of the line passing through the point -2 -3 and is perpendicular to the line 4x plus 3y -5 equals 0?
Perpendicular equation: 4x +3y -5 = 0 Perpendicular slope: -4/3 Slope of line: 3/4 Point of line: (-2, -3) Equation of line: y - -3=3/4(x - -2) => 4y - -12=3x - -6 => 4y = 3x -6 Therefore the equation of the line is: 4y = 3x -6 or 3x -4y -6 = 0
What is the equation and its perpendicular bisector equation of the line whose end points are at -2 3 and 1 -1 on the Cartesian plane?
Points: (-2, 3) and (1, -1) Midpoint: (-0.5, 1) Slope: -4/3 Perpendicular slope: 4/3 Equation: 3y = -4x+1 Perpendicular bisector equation: 4y = 3x+5.5
What is the perpendicular bisector equation of the line whose end points are at 3 5 and 7 11 on the Cartesian plane?
Points: (3, 5) and (7, 11) Midpoint: (5, 8) Slope: 3/2 Perpendicular slope: -2/3 Perpendicular equation: y-8=-2/3(x-5) => 3y-24=-2x+10 => 3y=-2x+34 Therefore the perpendicular bisector equation is: 3y = -2x+34
