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What is the equation of a line that contains the point (21) and is perpendicular to the line y 3x 4?
Wiki User
∙ 7y ago
If you mean the point of (2, 1) and the line y = 3x+4
Then the perpendicular slope is -1/3 and its equation works out as 3y = -x+5
Wiki User
∙ 7y ago
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What is the equation of a line that passes through the point 0 -3 and is perpendicular to a line with a slope of 4?
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
What is the equation of the line perpendicular to y equals 3x minus 7 that contains points 6 and 8?
In the Cartesian plane, each point has two coordinates. Point 6 and point 8 are not sufficiently uniquely defined.
What equation has a graph perpendicular to y equals 2x-3?
5
The line given by the equation y equals -8x is perpendicular to what line?
It would be perpendicular to a line with the equation Y = 1/8 X.
When a point lies on the y-axis what do you know about it's x-coordinate .?
The x-coordinate of any point on the y-axis is 0. The y-axis is a line perpendicular to the x-axis. Any point on a line perpendicular to the x-axis has the same x-coordinate. The y-axis is the line perpendicular to the x-axis through 0, and has the equation x = 0; similarly, the x-axis is the line perpendicular to the y-axis through 0 and has the equation y = 0.
What is the equation of the line that contains the point (21) and is perpendicular to the line y3x-4?
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
Find the equation of the line perpendicular to -9x 2y-3 that contains the poins 3-1?
"http://wiki.answers.com/Q/Find_the_equation_of_the_line_perpendicular_to_-9x_2y-3_that_contains_the_poins_3-1"
What is the equation of a line that is perpendicular to and passes through the point (4 6)?
That would depend on its slope which has not been given.
What is the equation of a line that passes through the point 0 -3 and is perpendicular to a line with a slope of 4?
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
What is the equation of the line passing through the point -2 -3 and is perpendicular to the line 4x plus 3y -5 equals 0?
Perpendicular equation: 4x +3y -5 = 0 Perpendicular slope: -4/3 Slope of line: 3/4 Point of line: (-2, -3) Equation of line: y - -3=3/4(x - -2) => 4y - -12=3x - -6 => 4y = 3x -6 Therefore the equation of the line is: 4y = 3x -6 or 3x -4y -6 = 0
What is perpendicular to the line 3x plus y equals 2?
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
What is the equation of the line perpendicular to y equals 3x minus 7 that contains points 6 and 8?
In the Cartesian plane, each point has two coordinates. Point 6 and point 8 are not sufficiently uniquely defined.
Can you write the equation of a line with one point on the line?
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
What equation has a graph perpendicular to y equals 2x-3?
5
What equation describes a line that passes through the point (-14) and is perpendicular to the line 4x-3y-9?
If you mean point (-1, 4) and equation of 4x-3y = -9 then y = 4/3x+3 Slope of equation: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13
What equation of the line that contains the point 1 -1 and 2 -2?
Choose the equation of the line that contains the points (1, -1) and (2, -2).
How do I write the equation of the line that passes through the given point and is perpendicular to the given line Write the answer in slope-intercept form?
The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.
