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Im guessing that the equation is 7x - 2y +3z= 19 so the answer is 7x + 3z= 19
To find the xy-trace, set z = 0 in the equation -5x - 2y - 3z = 10. Simplifying, we get -5x - 2y = 10. This is the equation of the xy-trace for the given plane.
5x 2y = 10
The equation is -2y + 16 = 10
Let's say that 5x + 2y + 3z = 10 is a line (that lives in a three dimensional space. When we let z = 0, the given line is projected on the xy-plane, and it will cut both x- and y-axis. So the equation of the trace line is 5x + 2y = 10. The line cut the x-axis at x = 2, and the y-axis at y = 5.
Im guessing that the equation is 7x - 2y +3z= 19 so the answer is 7x + 3z= 19
To find the xy-trace, set z = 0 in the equation -5x - 2y - 3z = 10. Simplifying, we get -5x - 2y = 10. This is the equation of the xy-trace for the given plane.
-5x-2y=10
5x 2y = 10
3x + 2y = 8 This is an equation. It could be the equation of a line.
The equation is -2y + 16 = 10
7x + 2y + 3z = 42 The plane intersects each coordinate plane, but since you are interested to know where the plane cuts y-axis, this will happen when the plane cuts xy-plane or yz-plane. So you can set z = 0, or x = 0. So, set z = 0, then the plane will cuts the xy-plane along the line 7x + 2y = 42. If x = 0, then the y-intercept is 42/2 = 21.
2y= 32 y=16
4
Equations: 2x-3y = 4 and 5x+2y = 1 Multiply all terms in 1st equation by 5 and all terms in 2nd equation by 2:- So: 10x-15y = 20 and 10x+4y = 2 Subtract the 2nd equation from the 1st equation: -19y = 18 => y = -18/19 By substitution the solutions are: x = 11/19 and y = -18/19
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
what is the slope of the line that has the equation 4x+2y=12?