=3
Yes, that's what a geometric sequence is about.
Sequences are a group of numbers that follow a certain pattern. There are two kinds of sequences, the arithematic sequence and geometric sequence. Arithematic sequence follows through addition (and subtraction). Geometric sequence follows throug multiplication (and division). Arithematic Sequence Example : 1, 6, 11, 16, 21 The pattern follows an addition of 5. Geometric Sequence Example : 1, 3, 9, 27, 81 The pattern follows a multiplication of 3
Of sorts. 1 3 6 10 15 would have a geometric representation, but would not fit the definition of a "geometric sequence". One example of a geometric representation of the sequence would be the number of total bowling pins as you add each row. The first row as 1 pin, the second has 2, then 3,4,5. 1 = 1 + 2 = 3 + 3 = 6 + 4 = 10 + 5 = 15
A geometric sequence is : a•r^n while a quadratic sequence is a• n^2 + b•n + c So the answer is no, unless we are talking about an infinite sequence of zeros which strictly speaking is both a geometric and a quadratic sequence.
No. Although the ratios of the terms in the Fibonacci sequence do approach a constant, phi, in order for the Fibonacci sequence to be a geometric sequence the ratio of ALL of the terms has to be a constant, not just approaching one. A simple counterexample to show that this is not true is to notice that 1/1 is not equal to 2/1, nor is 3/2, 5/3, 8/5...
No.
An example of an infinite geometric sequence is 3, 5, 7, 9, ..., the three dots represent that the number goes on forever.
Yes, that's what a geometric sequence is about.
a sequence of shifted geometric numbers
Sequences are a group of numbers that follow a certain pattern. There are two kinds of sequences, the arithematic sequence and geometric sequence. Arithematic sequence follows through addition (and subtraction). Geometric sequence follows throug multiplication (and division). Arithematic Sequence Example : 1, 6, 11, 16, 21 The pattern follows an addition of 5. Geometric Sequence Example : 1, 3, 9, 27, 81 The pattern follows a multiplication of 3
Of sorts. 1 3 6 10 15 would have a geometric representation, but would not fit the definition of a "geometric sequence". One example of a geometric representation of the sequence would be the number of total bowling pins as you add each row. The first row as 1 pin, the second has 2, then 3,4,5. 1 = 1 + 2 = 3 + 3 = 6 + 4 = 10 + 5 = 15
The ratio is 4.
A geometric sequence is : a•r^n while a quadratic sequence is a• n^2 + b•n + c So the answer is no, unless we are talking about an infinite sequence of zeros which strictly speaking is both a geometric and a quadratic sequence.
What is the sum of the first 27 terms of the geometric sequence -3, 3, - 3, 3, . . . ?
antonette taño invented geometric sequence since 1990's
A descending geometric sequence is a sequence in which the ratio between successive terms is a positive constant which is less than 1.
No. Although the ratios of the terms in the Fibonacci sequence do approach a constant, phi, in order for the Fibonacci sequence to be a geometric sequence the ratio of ALL of the terms has to be a constant, not just approaching one. A simple counterexample to show that this is not true is to notice that 1/1 is not equal to 2/1, nor is 3/2, 5/3, 8/5...