676=262
There are 90 palindromic numbers between 100 and 1000
1 to 1000. Pilandromic 108
1001,1111,1221,1331,1441,1551,1661,1771,1881,1991,2002,2112,2222,2332,2442,2552,2662,2772,2882,2992,3003,3113,3223,3333,3443,3553,3663,3773,3883,3993,4004,4114,4224,4334,4444,4554,4664,4774,4884,4994: 40 numbers in all.
11000
2100
Magsolve ka Naman boy!
5445 is one that I can think of
Palindromic numbers between 1 and 1000 are numbers that read the same forward and backward. The palindromic numbers in this range include single-digit numbers (1 to 9), two-digit numbers like 11, 22, 33, up to 99, and three-digit numbers such as 101, 111, 121, up to 999. Specifically, the three-digit palindromes follow the pattern ABA, where A and B are digits. In total, there are 199 palindromic numbers between 1 and 1000.
To find the number of palindromic numbers between 1000 and 10000, we need to consider that a palindrome is a number that reads the same forwards and backwards. For a four-digit number to be palindromic, the first and last digits must be the same, and the middle two digits must be the same. Therefore, the total number of palindromic numbers between 1000 and 10000 is determined by the number of options for the first two digits (10 options, 1-9 excluding 0) and the last two digits (10 options as well). This gives us a total of 10 * 10 = 100 palindromic numbers between 1000 and 10000.
There are 199 palindromic numbers between 0 and 1000. These include single-digit numbers (0-9), which total 10, and two-digit numbers (11, 22, ..., 99), which add up to 9. Additionally, there are 90 three-digit palindromic numbers, ranging from 101 to 999, that follow the format aba (where a and b are digits). Thus, the total is 10 (single-digit) + 9 (two-digit) + 90 (three-digit) = 109 palindromic numbers.
A palindromic number is a number that remains the same when its digits are reversed. Between 1000 and 2000, the possible palindromic numbers have the form "ABBA" where A and B are digits from 1 to 9. There are 9 options for A (1-9) and 10 options for B (0-9), but we exclude the case where A is 0. Therefore, there are 9 * 10 = 90 palindromic numbers between 1000 and 2000.
1100