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I believe this makes the 3-4-5 triangle, making the hypotenuse 15 cm

but just in case this is wrong, c^2 = sqrt(a^2 +b^2)

c^2 = sqrt(81+144)= sqrt(225)= 15

Answer: 15 cm

Q: What is the length of a diagonal of a rectangle whose base measure is 12Cm and whose height is 9Cm?

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To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).

If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square

Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2

The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.

The diagonal is 26cm

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To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).

If it's a rectangle and you know its length and height then use Pythagoras' theorem to find the length of its diagonal

If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square

The diagonal is 7.21 feet.

The length of the diagonal is about 16.03 feet.

Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2

The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.

The diagonal is 26cm

-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)

The diameter of a rectangle is the same as its diagonal (angle in a semicircle is a right angle). So the diagonal forms a right angled triangle with the diagonal as the hypotenuse and two sides of the rectangle (a length and a breadth) forming the legs of the triangle. If the lengths of the sides of the rectangle are known, a simple application of Pythagoras's theorem given the measure of the diagonal.

Using Pythagoras' theorem it works out as 194.9820505 or 195 centimeters

The diagonal length is about 18.44 inches.