I believe this makes the 3-4-5 triangle, making the hypotenuse 15 cm
but just in case this is wrong, c^2 = sqrt(a^2 +b^2)
c^2 = sqrt(81+144)= sqrt(225)= 15
Answer: 15 cm
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square
The diagonal is 26cm
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
If it's a rectangle and you know its length and height then use Pythagoras' theorem to find the length of its diagonal
If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square
The length of the diagonal is about 16.03 feet.
The diagonal is 26cm
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.
The diameter of a rectangle is the same as its diagonal (angle in a semicircle is a right angle). So the diagonal forms a right angled triangle with the diagonal as the hypotenuse and two sides of the rectangle (a length and a breadth) forming the legs of the triangle. If the lengths of the sides of the rectangle are known, a simple application of Pythagoras's theorem given the measure of the diagonal.
Using Pythagoras' theorem it works out as 194.9820505 or 195 centimeters
The diagonal length is about 18.44 inches.
This length (diagonal) = sq.rt ( l2 + b2 ) where 'l' is length of the rectangle and 'b' is the breadth of the rectangle.