t(n) = 29 - 7n where n = 1, 2, 3, ...
76
29. To find range, you subtract the lowest term, from the largest term. 39-10=29
Un = 29 - 9n
-22 -6 0 15 29
It is: nth term = 29-7n
The nth term is -7n+29 and so the next term will be -6
7n - 6
t(n) = 29 - 7n where n = 1, 2, 3, ...
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
5=22+12 8=22+22 13=22+32 20=22+42 29=22+52 40=22+62
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
76
nth term = 5 +8n
9n+2
is 219 in the sequence of 4n-3
2n +29