To find the nth term of a sequence, we first need to identify the pattern. In this case, it appears that the sequence is increasing by consecutive odd numbers: 3, 5, 7, 9, 11, etc. Therefore, the nth term can be calculated using the formula: nth term = a + (n-1)d, where a is the first term (5), n is the term number, and d is the common difference (3 for this sequence). So, the nth term for this sequence would be 5 + (n-1)3, which simplifies to 3n + 2.
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
nth term = 5 +8n
9n+2
It is: nth term = 29-7n
The nth term is -7n+29 and so the next term will be -6
t(n) = 29 - 7n where n = 1, 2, 3, ...
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
To find the nth term of a sequence, we first need to identify the pattern. In this case, it appears that the sequence is increasing by consecutive odd numbers: 3, 5, 7, 9, 11, etc. Therefore, the nth term can be calculated using the formula: nth term = a + (n-1)d, where a is the first term (5), n is the term number, and d is the common difference (3 for this sequence). So, the nth term for this sequence would be 5 + (n-1)3, which simplifies to 3n + 2.
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
76
nth term = 5 +8n
9n+2
2n +29
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
5 to 7 is 27 to 17 is 1017 to 19 is 219 to 29 is 1029 to 31 is 2there fore following the pattern the nth term is 4131 to 41 is 10