It is: nth term = 6n-4
[ 6n + 8 ] is.
8 + (74 x 6) = 75th term. nth term = 8 + 6(n-1)
It is: 26-8n
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
Tn = 10 + n2
[ 6n + 8 ] is.
It is: 26-6n
8 + (74 x 6) = 75th term. nth term = 8 + 6(n-1)
It is: 26-8n
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
It is: nth term = 7n-9
It is: nth term = 35-9n
Tn = 10 + n2
46n9
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
596
The common difference (d) between successive terms is -9. The first term (a) is 26 The formula for the nth term [a(n)] of an Arithmetic Series is , a + (n - 1)d. Inputting the values for a and d gives :- a(n) = 26 - 9(n - 1) = 26 - 9n + 9 = 35 - 9n......where n = 1,2,3......