Diags of rhombus form 4 Pythagorean triangles. If these triangles sides are 10 and 8 cm then hypotenuses would be 12.8 cm. Each hypotenuse is one side of the rhombus so perimeter would be 51.2 cm to nearest mm.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
It depends on what information you have: the length of a side, or the lengths of the diagonals, or a diagonal and an angle. Each of these will give rise to a different formula.
P = 4*a (a is side length) Area = p*q/2 (p=perimeter, q=diagonal
The length of the rhombus is equal to the length of the diagonal formed by the bisector of the 2 opposite acute angles.
Perimeter = 29 cm so each side is 7.25 cm. The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm. Therefore, the area of the rhombus is twice that = 49.7 square cm.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
It depends on what information you have: the length of a side, or the lengths of the diagonals, or a diagonal and an angle. Each of these will give rise to a different formula.
The length of the sides of the rhombus are 10cm, as a rhombus has equal sides. since the diagonals of a rhombus are perpendicular, ratio of side of rhombus to 1/2 a diagonal to 1/2 of another diagonal is 5:4:3 (pythagorean thriple), hence ratio of side of rhombus to 1 diagonal to another diagonal is 5:8:6. since 5 units = 10cm 8 units = 16cm 6 units = 12cm and there are your diagonals.
The length of one diagonal is not sufficient to determine its sides and so its perimeter.
The length of the other diagonal works out as 12cm
That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.
The answer to this question depends on what characteristic of a rhombus you are measuring: the length of its sides, its perimeter, area, length of diagonal, its acute angles, its obtuse angles, or something else.
Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40
P = 4*a (a is side length) Area = p*q/2 (p=perimeter, q=diagonal
"Congruent" isn't used to describe the diagonals of a rhombus. However, all four sides of a rhombus are congruent - they are all the same length.The diagonals of a rhombus are perpendicular to each other. They are not the same length - if the diagonals were the same length, then you would have a square.
The answer depends on which aspect of a rhombus. Its sides are of equal length but its diagonals are NOT!
Please note that the diagonals cross one another at right angles, and bisect one another. You should draw a diagram to visualize this. From this center point, where the diagonals cross, you have a RIGHT TRIANGLE that involves half of one diagonal, half of the other diagonal, and one of the sides of the rhombus. This lets you use the Pythagorean Theorem to solve for the length of the side.