Constructing the figure, we find the other diagonal to have length 10.
The area of the rhombus would thus be 10x8x0.5=40
A square with a perimeter of 48 meters has an area of 144 meters squared.
Let the other diagonal be x If: 0.5*12*x = 30 then x = 60/12 => x = 5 The rhombus has four interior right angle triangles with lengths of 6 cm and 2.5 cm Using Pythagoras each equal sides of the rhombus works out as 6.5 cm Perimeter: 4*6.5 = 26 cm
The area of a square which has a perimeter of 40 meters is: 100 m2
The diagonal of the garden is 20 meters.
20 meters.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
P = 4*a (a is side length) Area = p*q/2 (p=perimeter, q=diagonal
123
There is no relationship between the perimeter and the area of a rhombus. Take a rhombus with all 4 sides = 2 units. Therefore the perimeter is 8 units. There are an infinite number of possible areas for this rhombus. The largest possible area will be when the rhombus approaches the shape of a square = 4 square units. The smallest area will be when the one diagonal approaches 0 units and the other diagonal approaches 4 units (squashed almost flat). So two very extreme areas can have the same perimeter, including all those areas in-between.
The answer to this question depends on what characteristic of a rhombus you are measuring: the length of its sides, its perimeter, area, length of diagonal, its acute angles, its obtuse angles, or something else.
The room measures 16 meters x 8 meters and has a diagonal measurement of 17.9 meters.
Diagonals of a rhombus are perpendicular so the product is the area. If x is the smaller diagonal, the longer is 4x, and the area if 4x2.
Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter
63
310
That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.
Let the other diagonal be x:- If area is: 0.5*x*7.5 = 37.5 Then x is: 37.5/(0.5*7.5) = 10 The rhombus will then have 4 right angles with sides of 5 and 3.75 Using Pythagoras: hypotenuse of each triangle is 6.25 cm Therefore perimeter of the rhombus is: 4*6.25 = 25 cm