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When a die is rolled once, the probability of a 4 showing up is 1/6.

Apply the binomial probability for finding the probability of exactly three fours out of 12 throws of a die.

n=12 (number of throws)

p=1/6 (probability of a four in a single throw)

x = 3 (number of times out of 12 , a four showing up)

P(x=3) = 12C3 (1/6)^3 (5/6)^(12-3)

= 12C3 (1/6)^3 (5/6)^9 = 0.197443

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Q: What is the probability that 12 rolls of a die will show exactly three fours?
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