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What is the probability that the first die will have the same number as the second die?
Wiki User
∙ 13y ago
On six sided dice: 1 out of 6. If you make a chart:
- 1 - 2 - 3 - 4 - 5 - 6
1 11 12 13 14 15 16
2 21 22 23 24 25 26
3 31 32 33 34 35 36
4 41 42 43 44 45 46
5 51 52 53 54 55 56
6 61 62 63 64 65 66
See that 6 out of the 36 possibilities (or 1 out of 6) have doubles, meaning that the second die is the same as the first die.
Wiki User
∙ 13y ago
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What type of event is found by multiplying the probability of the first event by the probability of the second event?
That's the probability that both events will happen, possibly even at the same time. I think it's called the 'joint' probability.
What is the probability of winning two games with the same probability of 0.8?
The probability of winning two games with the same probability of 0.8 can be calculated by multiplying the probability of winning the first game (0.8) by the probability of winning the second game (0.8). Therefore, the probability is 0.8 * 0.8 = 0.64, or 64%.
What is the probability of rolling an even number on a die and rolling an odd number on a second roll of the same die?
0.25 ( P = 0.5 each time)
What is the probability of drawing a card from each of 2 decks and getting the two of clubs from both decks?
Let's say there are 52 cards in a deckThere's one chance out of 52 to get the two of clubs from the first deckThe same chance with the second deckThe probability that the two events occur at the same time is the probability of the first multiplied by the probability of the second as the events are independentSo P = 1/52 x 1/52 = 1/2074
What is the probability of two cards out of a deck of 52 being the same suit if the sampling is done with replacement?
There are four suits, each with an equal number of cards. It doesn't really matter what the first card is, we're just drawing it to get the name of the suit we're looking for on the second draw. So, since there are 4 suits and the probability of each of them is equal, then the overall probability is 1/4 that they're the same suit (and 1/52 that they're the same CARD, since you put it back after the first draw).
Two dice are thrown. What is the probability of getting the same number?
The first dice can show any number. However the second dice has a 1 in 6 chance of being the same as the first. Hence the probability of getting two numbers the same is 1/6.
What type of event is found by multiplying the probability of the first event by the probability of the second event?
That's the probability that both events will happen, possibly even at the same time. I think it's called the 'joint' probability.
What is the probability of winning two games with the same probability of 0.8?
The probability of winning two games with the same probability of 0.8 can be calculated by multiplying the probability of winning the first game (0.8) by the probability of winning the second game (0.8). Therefore, the probability is 0.8 * 0.8 = 0.64, or 64%.
What is the probability of rolling an even number on a die and rolling an odd number on a second roll of the same die?
0.25 ( P = 0.5 each time)
What is the probability that two students will think of the same letter of the alphabet at the same time?
I think it depends on how many students are thinking of alphabet letters at the same time :) The first student will think of a letter from the English alphabet. Then, the second student will think of a letter. The probability that the second student will select what the first student selected is 1/26.
What is the probability of drawing a card from each of 2 decks and getting the two of clubs from both decks?
Let's say there are 52 cards in a deckThere's one chance out of 52 to get the two of clubs from the first deckThe same chance with the second deckThe probability that the two events occur at the same time is the probability of the first multiplied by the probability of the second as the events are independentSo P = 1/52 x 1/52 = 1/2074
How many outcomes are there in the sample space for rolling 2 dice?
We calculate the numerator of the desired probability: There are 6 ways any number can show up on the first die AND There is only 1 way that same number can show up on the second die So since "AND" means "MULTIPLY", there are 6x1 or 6 ways that both dice can come up the same. So the numerator of the probability is 6. We calculate the denominator of the desired probability: There are 6 ways any number can show up on the first die AND There are 6 ways any number can show up on the second die So since "AND" means "MULTIPLY", there are 6x6 or 36 ways the two dice can all come up any number. So the denominator of the probability is 36.
What is the probability of rolling the same number 4 times?
The first number doesn't matter, just that the last three are the same as the first. P(rolling the same as the number before) = 1/6 P(rolling the same number as the first three times = (1/6)3 = 1/216
What is the probability of rolling a 1 2 or 3 on the first roll of a 1-6 number cube and rolling a 4 5 or 6 on the second roll of the same cube?
The probability of (1 or 2 or 3) on the first (or any) roll is 1/2 = 50% .The probability of (4 or 5 or 6) on the second (or any) roll is 1/2 = 50% .The probability of exactly that result on two rolls is (1/2 x 1/2)= (50% x 50%) = 1/4 = 25% .
Each of 3 people chose a number from 1-10 what is the probability that at least 2 people have the same number?
The probability that 2 people have the same number is 2 out of 10
A six sided die is rolled twice what is the probability of rolling either an even number on the first roll or a 1 on the second roll the answer is 7 over 12 but I can't figure out how to get there?
The question asks "What is the probability of rolling either an even number on the first roll or a 1 on the second roll?" These events are independent from each other as the outcome of the second roll is not affected by the outcome of the first roll. However, these events are non-mutually exclusive, meaning that these events can both occur at the same time.The probability of rolling an even number on the first roll is 3/6 because 2, 4, and 6 are even numbers and a six-sided die has six possible numbers.The probability of rolling a 1 on the second roll is 1/6.If these two probabilities are added together, we will have "double counted" the event where an even number is rolled on the first roll and a 1 is rolled on the second roll. To correct for this, we must subtract the probability of both events occurring.The probability that both events occur is 3/36, because 3/6 * 1/6 = 3/36.Now, the probability of rolling either an even number on the first roll or a 1 on the second roll is:3/6 + 1/6 - 3/36= 18/36 + 6/36 - 3/36= 21/36= 7/12
What is the probability of rolling the same number when three number cubes are rolled?
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
