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Q: What is the remainder when 2x4 plus 5x3 - 17x2 - 5 is divided by x plus 3?

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Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. If the question is about the remainder for 2x4 + 5x3 - 17x2 - 5 divided by x + 3 by the remainder theorem, to get the answer you first find the value of x tha t makes x + 3 = 0. That is x = -3. You then substitute this value in the "numerator" expression: Thus remainder = 2*(-3)4 + 5*(-3)3 - 17*(-3)2 - 5 = 2*81 - 5*27 - 17*9 - 5 = -131

(2x4) + (8x3) + 18x 8 + 24 + 18x 32 + 18x

the answer is 0!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! I was the one who made it an unanwser question?

2x4 - 9x3 + 13x2 - 15x + 9 = 2x4 - 6x3 - 3x3 + 9x2 + 4x2 - 12x - 3x + 9 = 2x3(x - 3) - 3x2(x - 3) + 4x(x - 3) - 3(x - 3) = (x - 3)*(2x3 - 3x2 + 4x - 3) So the quotient is (2x3 - 3x2 + 4x - 3) and the remainder is 0.

2x4

14 ________________ 14

The final answer is 112.

8 divided by 4 = 2

A fifth degree polynomial.

The GCF is 2x4

10

2x^3 - 3x^2 + 4x - 3

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