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51
There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2
Fibonacci numbers are the numbers in a sequence defined as follows: N1 = 1 N2 = 1 and after that, each number is the sum of the last two numbers in the sequence. N3 = N1 + N2 N4 = N2 + N3 and so on.
It appears to be increasing in difference by 2. The nth number is n2 +2. 1*1+2=3 2*2+2=6 3*3+2=11
a0= 1 , a1=2, an= n2+1I'm sure there are more. This is the simplest one I could think of.
51
There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2
Fibonacci numbers are the numbers in a sequence defined as follows: N1 = 1 N2 = 1 and after that, each number is the sum of the last two numbers in the sequence. N3 = N1 + N2 N4 = N2 + N3 and so on.
3 Mg + N2 = Mg3N2
Un = n3 + n2 - 3n - 2 for n = 1, 2, 3, ...
n2
It is T(n) = n2 - 2n + 6
n2-3n+2
(1/2n-r)2+((n2+2n)/4) where n is the row number and r is the position of the term in the sequence
n1= 25 n2= n1+1 n3= n1-1 n4=n1+2 n5=n1-2
There are infinitely many possible answers. The simplest, perhaps, is Un = (n2 - n + 4)/2
(N2) + 3(H2) = 2(NH3)