Heads - ½
Tails - ½
There are two reasonable outcomes of flipping a coin. You could get heads or tails. Some might argue that the third outcome is that the coin will land on the edge.
A system with two possible outcomes with equal probabilities.
2*2*6 = 24 outcomes.
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
There are 12.
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
enless you include it landing on it's side the two possible outcomes for this are: Heads and Tails
A system with two possible outcomes with equal probabilities.
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
The event is that the coin lands with the Heads on top.
2*2*6 = 24 outcomes.
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
Each coin can come out either heads (H) or tales (T). Since you're tossing four coins at once, I'm assuming there is no sense of order to be accounted for. In that case, the possible outcomes are the following: HHHH HHHT HHTT HTTT TTTT
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
To determine the amount of possible outcomes, there must be a number of sections for each spinner
There are 12.
Number of possible outcomes of one coin = 2Number of possible outcomes of six coins = 2 x 2 x 2 x 2 x 2 x 2 = 64Number of possible outcomes with six heads = 1Probability of six heads = 1/64Probability of not six heads = at least one tails = 63/64 = 98.4375%