If you mean y = 4x-1 then the slope is 4 and the y intercept is -1
Without an equality sign the given terms can't be considered to be a straight line equation.
If you mean: y = 4x+5 then the perpendicular slope is -1/4
-5
The straight line equation is: y = -4x+1
The equation, y = -4x - 3, is written in what's called slope-intercept form. The general equation for slope-intercept form is y = mx + b, where m is the slope of the line, and b is the y-intercept. So, for the equation in question, m = -4 and b = -3. Thus, the slope of the line is -4.
what is the slope of the line that has the equation 4x+2y=12?
3
Without an equality sign the given terms can't be considered to be a straight line equation.
Slope = 4
If the equation is x+4 the slope is 1. If the equation is 4x than the slope is 4.
Parallel lines have the same slope. So if you put the equation 4x + y -1 = 0 into the slope-intercept form of the equation of a line (y = mx + b), you can read the slope, m, from it. Rearranging that equation gives: y = -4x + 1. The slope of both lines is -4. If the new line passes through the (x, y) point (1, 2), you can use the point-slope form of the equation of a line and plug in the values to find the equation of the new line: y - y1 = m(x - x1) y - 2 = -4(x - 1) y - 2 = -4x + 4 y = -4x + 6
If you mean: y = 4x+5 then the perpendicular slope is -1/4
10
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
The slope is -4
-5
The straight line equation is: y = -4x+1