If you mean y = 4x-1 then the slope is 4 and the y intercept is -1
Without an equality sign the given terms can't be considered to be a straight line equation.
If you mean: y = 4x+5 then the perpendicular slope is -1/4
To find a line that is parallel to the line represented by the equation ( y - 4x + 5 = 0 ), we first rewrite it in slope-intercept form: ( y = 4x - 5 ). The slope of this line is 4. A parallel line will have the same slope, so a general equation for a parallel line can be expressed as ( y = 4x + b ), where ( b ) is any real number.
-5
The straight line equation is: y = -4x+1
what is the slope of the line that has the equation 4x+2y=12?
3
Without an equality sign the given terms can't be considered to be a straight line equation.
Slope = 4
If the equation is x+4 the slope is 1. If the equation is 4x than the slope is 4.
If you mean: y = 4x+5 then the perpendicular slope is -1/4
Parallel lines have the same slope. So if you put the equation 4x + y -1 = 0 into the slope-intercept form of the equation of a line (y = mx + b), you can read the slope, m, from it. Rearranging that equation gives: y = -4x + 1. The slope of both lines is -4. If the new line passes through the (x, y) point (1, 2), you can use the point-slope form of the equation of a line and plug in the values to find the equation of the new line: y - y1 = m(x - x1) y - 2 = -4(x - 1) y - 2 = -4x + 4 y = -4x + 6
10
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
The slope is -4
-5
The straight line equation is: y = -4x+1