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Q: What is the smallest numeral that must be add to 486 to make it exactly divisible by 23?

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330

It is 8961 - W*int(8961/W)

By simply putting the numbers next to one another, smallest = 25 largest = 52 If mathematical functions are permitted, I propose smallest = 2-5! which is approx 7.5*10-37 and largest = 52! which is approx 8.1*1067 But I could be wrong!

316548/375 =844 quotient,48 remainder Dividend- remainder=divisor *quotient 316548-48=375*844 which gives 316500. Compare both that is 316548 and 316500 difference is 48. 48 is to be subracted.

The roman numeral for 5 is: V

Related questions

339 + 1 = 340,which is exactly divisible.

Add 7 cents to 2.45 . Now you have 2.52, which can be divided into 9 equal shares of 28 cents each.

6 (or 0)

403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.

Seven

0.

330

6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).

It is 8961 - W*int(8961/W)

(560 ÷ 25) − 0.4 = 22 Therefore, the smallest number to subtract from 560 is 0.4 * 25 = 10

124/3 = 41 quotient, remainder 1 Increase quotient 42*3 = 126. difference of 126 and 124 is 2 . So 2 is to be added it is least.

By simply putting the numbers next to one another, smallest = 25 largest = 52 If mathematical functions are permitted, I propose smallest = 2-5! which is approx 7.5*10-37 and largest = 52! which is approx 8.1*1067 But I could be wrong!