20
To determine the smallest number that must be added to 403 to make it divisible by 8, first find the remainder when 403 is divided by 8. The remainder is 3 (since 403 ÷ 8 = 50 with a remainder of 3). To make it divisible by 8, you need to add 5 (8 - 3 = 5). Therefore, the smallest number to add is 5.
To determine the smallest number that must be added to 5621 to make it divisible by 12, we first find the remainder of 5621 when divided by 12. Dividing 5621 by 12 gives a remainder of 5. Therefore, to make 5621 divisible by 12, we need to add (12 - 5 = 7). Thus, the smallest number to add is 7.
To find the number that should be subtracted from 63700 to make it exactly divisible by 18, first, calculate the remainder when 63700 is divided by 18. Dividing 63700 by 18 gives a quotient of 3538 and a remainder of 16. Therefore, to make 63700 divisible by 18, you need to subtract this remainder (16) from 63700. Thus, subtracting 16 will yield 63684, which is divisible by 18.
To find the least number that must be subtracted from 13601 to make it exactly divisible by 87, we first calculate the remainder when 13601 is divided by 87. Performing the division, we find that ( 13601 \div 87 ) gives a quotient of 155 and a remainder of 26. To make 13601 divisible by 87, we need to subtract this remainder from 13601. Therefore, we need to subtract 26, resulting in ( 13601 - 26 = 13575 ), which is exactly divisible by 87.
330
339 + 1 = 340,which is exactly divisible.
To find the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9, we first need to determine the remainder when 2.45 is divided by 9. 2.45 can be written as 245/100. When 245 is divided by 9, the remainder is 8. To make 2.45 exactly divisible by 9, we need to add the difference between 9 and the remainder, which is 9 - 8 = 1. Therefore, the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9 is $0.01.
6 (or 0)
To determine the smallest number that must be added to 403 to make it divisible by 8, first find the remainder when 403 is divided by 8. The remainder is 3 (since 403 ÷ 8 = 50 with a remainder of 3). To make it divisible by 8, you need to add 5 (8 - 3 = 5). Therefore, the smallest number to add is 5.
To determine the smallest number that must be added to 5621 to make it divisible by 12, we first find the remainder of 5621 when divided by 12. Dividing 5621 by 12 gives a remainder of 5. Therefore, to make 5621 divisible by 12, we need to add (12 - 5 = 7). Thus, the smallest number to add is 7.
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
0.
To find the number that should be subtracted from 63700 to make it exactly divisible by 18, first, calculate the remainder when 63700 is divided by 18. Dividing 63700 by 18 gives a quotient of 3538 and a remainder of 16. Therefore, to make 63700 divisible by 18, you need to subtract this remainder (16) from 63700. Thus, subtracting 16 will yield 63684, which is divisible by 18.
Well, darling, the smallest number you can take from 4979 to make it divisible by 47 is 6. Why? Because when you subtract 6 from 4979, you get 4973, which is divisible by 47. Simple math, honey, nothing to stress about.
Seven
To find the least number that must be subtracted from 13601 to make it exactly divisible by 87, we first calculate the remainder when 13601 is divided by 87. Performing the division, we find that ( 13601 \div 87 ) gives a quotient of 155 and a remainder of 26. To make 13601 divisible by 87, we need to subtract this remainder from 13601. Therefore, we need to subtract 26, resulting in ( 13601 - 26 = 13575 ), which is exactly divisible by 87.
330