20
To determine the smallest number that must be added to 5621 to make it divisible by 12, we first find the remainder of 5621 when divided by 12. Dividing 5621 by 12 gives a remainder of 5. Therefore, to make 5621 divisible by 12, we need to add (12 - 5 = 7). Thus, the smallest number to add is 7.
To determine the smallest number that must be added to 403 to make it divisible by 8, first find the remainder when 403 is divided by 8. The remainder is 3 (since 403 ÷ 8 = 50 with a remainder of 3). To make it divisible by 8, you need to add 5 (8 - 3 = 5). Therefore, the smallest number to add is 5.
To find the number that should be subtracted from 63700 to make it exactly divisible by 18, first, calculate the remainder when 63700 is divided by 18. Dividing 63700 by 18 gives a quotient of 3538 and a remainder of 16. Therefore, to make 63700 divisible by 18, you need to subtract this remainder (16) from 63700. Thus, subtracting 16 will yield 63684, which is divisible by 18.
330
It is 8961 - W*int(8961/W)
339 + 1 = 340,which is exactly divisible.
To find the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9, we first need to determine the remainder when 2.45 is divided by 9. 2.45 can be written as 245/100. When 245 is divided by 9, the remainder is 8. To make 2.45 exactly divisible by 9, we need to add the difference between 9 and the remainder, which is 9 - 8 = 1. Therefore, the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9 is $0.01.
6 (or 0)
To determine the smallest number that must be added to 5621 to make it divisible by 12, we first find the remainder of 5621 when divided by 12. Dividing 5621 by 12 gives a remainder of 5. Therefore, to make 5621 divisible by 12, we need to add (12 - 5 = 7). Thus, the smallest number to add is 7.
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
0.
To find the number that should be subtracted from 63700 to make it exactly divisible by 18, first, calculate the remainder when 63700 is divided by 18. Dividing 63700 by 18 gives a quotient of 3538 and a remainder of 16. Therefore, to make 63700 divisible by 18, you need to subtract this remainder (16) from 63700. Thus, subtracting 16 will yield 63684, which is divisible by 18.
Well, darling, the smallest number you can take from 4979 to make it divisible by 47 is 6. Why? Because when you subtract 6 from 4979, you get 4973, which is divisible by 47. Simple math, honey, nothing to stress about.
330
Seven
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
It is 8961 - W*int(8961/W)