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It is 50*51/2 = 1275.
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∙ 9y ago
The sum of the numbers 1 through 50 can be found using the formula for the sum of an arithmetic series: [(n/2) * (first term + last term)], where n is the number of terms. In this case, n = 50 and the first term is 1 and the last term is 50. Plugging those values into the formula, the sum is 1275.
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What is the sum of the numbers 1-50?
51
What is the sum of all the natural numbers from 1 to 50?
(n)( n+1)/2 where n = 50. (50 x 51)/2 = 2,525
What is the sum of the first fifty consecutive add numbers?
rearrange 1 to 50 so that you see this pattern: 50 = 50 1+49 = 50 2+48 = 50 ... 24+26 = 50 25 = 25 then add this up: 25 x 50 + 25 = 1275
What is the porbability that a coin tossd in the air will land with heads up?
1/2, or 50%.1/2, or 50%.1/2, or 50%.1/2, or 50%.
What is sum of the first 100 whole numbers?
It is instructive to note that you can rewrite 1+2+3+4....+99+100 as 1+100+2+99+3+98....+50+51 Then you can group each pair of numbers as (1+100)+(2+99)+(3+98)+...+(50+51) All of these couplets add up to 101, and there are 50 of them. Thus the sum of the first 100 whole numbers is 50x101. This can be calculated at 5,050.
What is the sum of the first 50 natural numbers?
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
What is the sum of the numbers 1-50?
51
What is the sum of odd numbers from 1 to 100?
Using the formula for the sum of an arithmetic sequence;Sum = 1/2*n [n is the total number of terms] *(2a [a is the value of the first term] + (n-1) * d)[d is the common difference between each term]So the formula looks like this: Sum = 1/2*n (2a+(n-1)*d)n = 50 because there's 50 odd numbers in a hundred and 50 even numbers (50+50=100)a = 1d = 2So inputting the values gives:Sum= 1/2*50 (2*1+(50-1)* 2)Sum= 25*(2+49*2)Sum= 25*(2+98)Sum= 25*(100)Sum= 2500Answer= 2,500
What is the sum of the factors of 50?
Here are the factor pairs of 50:1 and 502 and 255 and 10Now add them up: 1 + 50 + 2 + 25 + 5 + 10 = 93
How would you find the sum of the first 50 even numbers?
Sum of 1st n even numbers: count*average = n * (2 + 2*n)/2 = n * (n+1) Sum = 50 * (2+100)/2 = 50*51 = 2550
What is the sum of all the natural numbers from 1 to 50?
(n)( n+1)/2 where n = 50. (50 x 51)/2 = 2,525
What is the sum of all the factors of 50?
1 + 2 + 5 + 10 + 25 + 50 = 93
Wap to find the sum of series 1 plus 2 plus 3 plus - - - plus 100?
Sum of numbers from 1 to 100:(1+100) + (2+99) + (3+98) + (4+97) + ... + (49+52) + (50+51) =50 pairs, each pair adds up to 101= (50 x 101)= 5,050
What is the sum of the first fifty consecutive add numbers?
rearrange 1 to 50 so that you see this pattern: 50 = 50 1+49 = 50 2+48 = 50 ... 24+26 = 50 25 = 25 then add this up: 25 x 50 + 25 = 1275
What is the porbability that a coin tossd in the air will land with heads up?
1/2, or 50%.1/2, or 50%.1/2, or 50%.1/2, or 50%.
What is the sum of the numbers from 1 to 100?
Sum of first n natural numbers is (n) x (n + 1)/2 Here we have the sum = 100 x (101)/2 = 50 x 101 = 5050
What is the sum of the numbers from 1 to 50?
Sum of first n integers = n/2(n+1), in this case 25 x 51 = 1275
