10+20+30 = 60
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975
Oh, what a happy little question! To find the sum of the first 500 multiples of 3, we can use the formula for the sum of an arithmetic series: (n/2) * (first term + last term). In this case, the first term is 3 and the last term is 3 * 500. Plugging these values in, we get (500/2) * (3 + 1500) = 250 * 1503 = 375,750.
The first five multiples of 10 are 10,20,30,40,50.... 1 * 10 = 10 2 * 10 = 20 3 * 10 = 30 4 * 10 = 40 5 * 10 = 50
10
The anser to that Q is 30.