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What is the sum of the first 33 terms of the following sequence 8 17 26?
Wiki User
∙ 13y ago
5016. Here's how:
Each term is 1 less than the terms in 9, 18, 27 ..., which is the sequence 9*N, with N = 1..33.
So the actual formula for the sequence is {9*N - 1}
The sequence 1,2,3...N can be summed by (N+1)*N/2 --> N=33: (33+1)*33/2 = 561, so the sum of the first 33 terms of 9+18+27+297 = 9*(1+2+3+..+33) = 9*561 = 5049. But our sequence terms are each one less than the terms in 9,18,27, so subtract 33 from 5049 = 5016.
Wiki User
∙ 13y ago
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Find the sum of the first 48 terms of an aritmetic sequance 2 4 6 8?
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Find the sum of the first 48 terms of an aritmetic sequance 2 4 6 8?
Sum of 1st 2 terms, A2 = 2 + 4 = 6 Sum of 1st 3 terms, A3 = 2 + 4 + 6 = 12 Sum of 1st 4 terms A4 = 2 + 4 + 6 + 12 = 20 you can create a formula for the sum of the 1st n terms of this sequence Sum of 1st n terms of this sequence = n2 + n so the sum of the first 48 terms of the sequence is 482 + 48 = 2352
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